What is the 20th term of the sequence that begins -3,6,-12,24....?
@Jhannybean ?
this is a geometric sequence with a common factor of -2 Nth term of a geometric sequence is given by the formula\[a _{n} = a _{1} r ^{(n-1)}\]
n= no. of the term you want to find and r is the common ratio = -2
n = 20 here
This is more of a geometric sequence. You can figure this out if you divide the preceding term by the previous term, so 6/-3 =-2. -12/6 =-2 24/-12 = -2 in a Geometric Sequence, we have ratios instead of "differences (d)" and it follows the equation \[\large a_{n}= a_{1}r^{n-1}\]
dammit rajee.....-_- I was explaining to him the difference between two two equations he was confused with, lol.
so 20th term would be \[\large a_{20}= (-3)(-2)^{20-1}\] r= -2 and a1 = -3 Now you can simplify it and you'll have your answer
Im a girl lol and I think I did it wrong.
Oh sorry :\ how did you do it?
I did the () first but idk what to do.. lol
the what part first?
Remember, follow PEMDAS.
\[\large a_{50}=(-3)(-2)^{19}\] you can either find what (-2)^19 equals, or punch the whole thing into your calculator and solve it that way :)
I divided first or multiply?
There is no division xD
I'd say multiply the (-2)^19 out FIRST and then MULTIPLY it to the (-3)
so... (-3)(-524288)
1572864?
You. are. correct :D
Thanksss :)
No problemo
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