how do i find the percent composition for this
pb02

Question

how do i find the percent composition for this 
     pb02

abb0t · Answer

Find the mass of each individual element and divide by the molar mass. then multiply by 100%.

nincompoop · Answer

I am not sure what pb is and 02 so the answer to your question is unknown. there's not one element in there

thomaster · Answer

$\sf\large PbO_2~=~Lead~dioxide~\ddot\smile$

thomaster · Answer

i think he means that :P

nincompoop · Answer

that could have been Phosphorus and Boron

thomaster · Answer

true :P phosphorus boron oxygen

thomaster · Answer

meh we'll see when @dave6heat responds :)

abb0t · Answer

Don't just assume, @thomaster !! That's so rude!

anonymous · Answer

um guys it's lead dioxide so whats the percent composition

abb0t · Answer

Like I said up above: Find the mass of each individual element and divide by the molar mass. then multiply by 100%.

abb0t · Answer

You may want to take out your periodic table for this.

anonymous · Answer

yes i have my periodic table thanks

nincompoop · Answer

then start counting masses, sum them all up and then like what abb0t said compare each element or allotrope against that sum and then multiply it by 100.

nincompoop · Answer

Pb = 207.2 amu x 1 = 207.2 amu
O = 15.999 amu x 2 =  31.998 amu

207.2 + 31.998 = 239.198

$$(207.2 \div 239.198) \times 100 =$$
$$(31.998 \div 239.198) \times 100 = $$