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Mathematics 18 Online
OpenStudy (anonymous):

Help?

OpenStudy (anonymous):

OpenStudy (anonymous):

@amistre64 @.Sam.

OpenStudy (anonymous):

@robtobey

OpenStudy (anonymous):

@radar @RadEn

OpenStudy (luigi0210):

For the first one multiply both sides by a common factor..

OpenStudy (anonymous):

@Luigi0210 what would that give me?? I have trouble on this, sorry to be a bother

OpenStudy (luigi0210):

\[\frac{ 1 }{ 3x+9 }*3(x+3)-\frac{ 1 }{ x+3 }*3(x+3)=2*3(x+3)\] \[1-6=2(3x+9)\]

OpenStudy (anonymous):

@Luigi0210 so what is the answer??? sorry again

OpenStudy (luigi0210):

Solve it out :/

OpenStudy (luigi0210):

\[-5=6x+18\] \[-23=6x\]

OpenStudy (anonymous):

@Luigi0210 would it be c?

OpenStudy (luigi0210):

no :/

OpenStudy (anonymous):

@Luigi0210 ahh... a?

OpenStudy (luigi0210):

.. :/

OpenStudy (luigi0210):

\[x=-\frac{ 23 }{ 6 }\]

OpenStudy (anonymous):

@Luigi0210 ohhh! what about the next???

OpenStudy (anonymous):

@Luigi0210 i got D... :/ is that wrong>?

OpenStudy (luigi0210):

you were close ^_^'

OpenStudy (anonymous):

@Luigi0210 oh, good :D

OpenStudy (luigi0210):

\[\frac{ 8 }{ x }*x^2+\frac{ 12 }{ x^2 }*x^2=-1*x^2\] \[8x+15=-x^2\] \[x^2+8x+15=0\] \[(x+3)(x+5)=0\]

OpenStudy (anonymous):

@Luigi0210 but it isn't D, so.. which would it be??(:

OpenStudy (anonymous):

@Luigi0210 yore the best

OpenStudy (luigi0210):

^_^'

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