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@amistre64 @.Sam.
@robtobey
@radar @RadEn
For the first one multiply both sides by a common factor..
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@Luigi0210 what would that give me?? I have trouble on this, sorry to be a bother
\[\frac{ 1 }{ 3x+9 }*3(x+3)-\frac{ 1 }{ x+3 }*3(x+3)=2*3(x+3)\] \[1-6=2(3x+9)\]
@Luigi0210 so what is the answer??? sorry again
Solve it out :/
\[-5=6x+18\] \[-23=6x\]
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@Luigi0210 would it be c?
no :/
@Luigi0210 ahh... a?
.. :/
\[x=-\frac{ 23 }{ 6 }\]
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@Luigi0210 ohhh! what about the next???
@Luigi0210 i got D... :/ is that wrong>?
you were close ^_^'
@Luigi0210 oh, good :D
\[\frac{ 8 }{ x }*x^2+\frac{ 12 }{ x^2 }*x^2=-1*x^2\] \[8x+15=-x^2\] \[x^2+8x+15=0\] \[(x+3)(x+5)=0\]
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@Luigi0210 but it isn't D, so.. which would it be??(:
@Luigi0210 yore the best
^_^'
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