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OpenStudy (rajee_sam):
can't you use a calculator?
OpenStudy (anonymous):
nope no calculator
OpenStudy (reemii):
tan(x)=tan(x-pi), and tan(-x)=-tan(x).
+ use tan(pi/6)=\(\frac{\sqrt3}{3}\)
OpenStudy (anonymous):
so -sqrt3?
OpenStudy (reemii):
no.
tan(5pi/6) = tan(-pi/6) = ...
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OpenStudy (anonymous):
-18.8496?
OpenStudy (allank):
It is really helpful to get the unit circle with trig function values in your head.
OpenStudy (allank):
With that in mind, I'd do it this way:
We know that tan 5pi/6 = [sin (5pi/6)]/[cos(5pi/6)]
Then using the lovely unit circle in my head, I get that
[sin (5pi/6)]/[cos(5pi/6)] = (1/2) / (-sqrt(3)/2) = -2/2sqrt(3)
OpenStudy (anonymous):
The answers I have are
-sqrt 3
-1/sqrt3
-1
1/sqrt3
OpenStudy (allank):
Great. Then you're good to go...unless u have questions regarding the working out..
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OpenStudy (anonymous):
which one is the answer for it?
OpenStudy (allank):
Simplify the solution I gave.
OpenStudy (anonymous):
soo 1/sqrt3?
OpenStudy (allank):
Hmm...what happened to the -ve sign?
OpenStudy (anonymous):
oooh ok -1/sqrt3
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OpenStudy (allank):
Yes. And definitely commit the trig unit circle to memory.