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Mathematics 20 Online
OpenStudy (anonymous):

What is tan 5pi/6?

OpenStudy (rajee_sam):

can't you use a calculator?

OpenStudy (anonymous):

nope no calculator

OpenStudy (reemii):

tan(x)=tan(x-pi), and tan(-x)=-tan(x). + use tan(pi/6)=\(\frac{\sqrt3}{3}\)

OpenStudy (anonymous):

so -sqrt3?

OpenStudy (reemii):

no. tan(5pi/6) = tan(-pi/6) = ...

OpenStudy (anonymous):

-18.8496?

OpenStudy (allank):

It is really helpful to get the unit circle with trig function values in your head.

OpenStudy (allank):

With that in mind, I'd do it this way: We know that tan 5pi/6 = [sin (5pi/6)]/[cos(5pi/6)] Then using the lovely unit circle in my head, I get that [sin (5pi/6)]/[cos(5pi/6)] = (1/2) / (-sqrt(3)/2) = -2/2sqrt(3)

OpenStudy (anonymous):

The answers I have are -sqrt 3 -1/sqrt3 -1 1/sqrt3

OpenStudy (allank):

Great. Then you're good to go...unless u have questions regarding the working out..

OpenStudy (anonymous):

which one is the answer for it?

OpenStudy (allank):

Simplify the solution I gave.

OpenStudy (anonymous):

soo 1/sqrt3?

OpenStudy (allank):

Hmm...what happened to the -ve sign?

OpenStudy (anonymous):

oooh ok -1/sqrt3

OpenStudy (allank):

Yes. And definitely commit the trig unit circle to memory.

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