Please help, I will give medal and become a fan if the answer is correct
Given: Line segment AB is perpendicular to line segment FC Line segment DE is perpendicular to line segment FC line segment AB is congruent to line segment DE ∠DEF ≅ ∠BAC Statement Reason Line segment AB is perpendicular to line segment FC Line segment DE is perpendicular to line segment FC line segment AB is congruent to line segment DE ∠DEF ≅ ∠BAC Given ∠FDE = 90˚ and ∠ABC = 90˚ Definition of Perpendicular Lines ∠FDE ≅ ∠ABC Substitution ΔABC ≅ ΔEDF Angle-Side-Angle Which figure correctly displays this proof?
@jim_thompson5910
Hint: It's given that AB is perpendicular to FC
so this means that AB and FC a) connect, intersect, or touch b) they meet at right angles (or 90 degree angles)
Last one?
good
that's the only one that fits the descriptions I posted
Can u help me with some more please ill medal and thanks
ok a few more
Which of the following statements will guarantee that ΔZWU ≅ ΔVUW? Quadrilateral ZWVU is a square. Line segment ZW is parallel to line segment UV ∡ZUV and ∡WVU measure 90°. Line segment ZU ≅ Line segment WV
soo?
one sec
ok no prob
If you were to divide a square by it's diagonal, what would you get
two triangles
right
what kind of triangles
so now what?
what kind of triangles form
right ones
are they congruent triangles
oh ya
how do you know
So now that we've established that, what now?
well those two triangles are congruent (you can use the SSS property to show it's true) so that guarantees you'll have 2 congruent triangles
What answer choice should I choose because that's not a choice
what shape did we start with
square
so dividing up a square along its diagonal guarantees you'll have 2 congruent triangles
so A?
correct, that's one way to guarantee you'll get those 2 triangles to be congruent
OK can I ask a few more there simple as you can see
alright 2 more
Which fact could you use to help prove that ΔAEDΔBEC using Side-Angle-Side? Line segment AD is parallel to line segment CB. Line segment CE over line segment DE is equal to line segment BE over line segment AE. The measure of line segment CE is equal to one-third times the measure of line segment DE. Line segment AD is congruent to line segment CB.
Which fact could you use to help prove that ΔAEDΔBEC using Side-Angle-Side? Line segment AD is parallel to line segment CB. Line segment CE over line segment DE is equal to line segment BE over line segment AE. The measure of line segment CE is equal to one-third times the measure of line segment DE. Line segment AD is congruent to line segment CB.
whenever you use the SAS similarity postulate, you use the idea that the sides are proportional to each other
so what does that mean
They are similar
so now what?
if two triangles are similar, then the corresponding sides form a ratio
so option B?
correct
OK :) last one
1.For the dilation, what was your scale factor? 2.For the reflection, across which line did you reflect it? 3.For the rotation, how many degrees was it rotated and in which direction?
@jim_thompson5910
I know the labels are wrong I already fixed the reflection and 180 degree counterclockwise turn
what's your question about this one
1.For the dilation, what was your scale factor? 2.For the reflection, across which line did you reflect it? 3.For the rotation, how many degrees was it rotated and in which direction?
you have the dilation labeled on your paper
the scale factor of the dilation
the rotation you have is incorrect
I know I told u I fixed that
how do I find the scale factor for the dilation
you already found it, it's 2
Ok next question lol
O must be losing my eyes lol
if you were to rotate the original figure 180 degrees, it won't go from Q1 to Q4
I fixed that already.How do I find out which line I reflected the image over.
ok, the reflected image is in Q4 right?
The image that I wrote was rotated is actually reflected, and the other new figure next to it was a 180 degree turn counterclockwise from the original
i see
so they're flipped
Would that be correct?
you're reflecting over the x-axis which is the line y = 0
yes that's correct
So what do I write. I reflected over line y=0?
yep
Thank You I wish u could help me more but a deal is a deal.
hopefully you can use the info learned here to apply it to the others I don't want to do it all for you
OK :) Thanks have a good night
yw, you too
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