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Mathematics 18 Online
OpenStudy (anonymous):

Please help, I will give medal and become a fan if the answer is correct

OpenStudy (anonymous):

Given: Line segment AB is perpendicular to line segment FC Line segment DE is perpendicular to line segment FC line segment AB is congruent to line segment DE ∠DEF ≅ ∠BAC Statement Reason Line segment AB is perpendicular to line segment FC Line segment DE is perpendicular to line segment FC line segment AB is congruent to line segment DE ∠DEF ≅ ∠BAC Given ∠FDE = 90˚ and ∠ABC = 90˚ Definition of Perpendicular Lines ∠FDE ≅ ∠ABC Substitution ΔABC ≅ ΔEDF Angle-Side-Angle Which figure correctly displays this proof?

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

Hint: It's given that AB is perpendicular to FC

jimthompson5910 (jim_thompson5910):

so this means that AB and FC a) connect, intersect, or touch b) they meet at right angles (or 90 degree angles)

OpenStudy (anonymous):

Last one?

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

that's the only one that fits the descriptions I posted

OpenStudy (anonymous):

Can u help me with some more please ill medal and thanks

jimthompson5910 (jim_thompson5910):

ok a few more

OpenStudy (anonymous):

Which of the following statements will guarantee that ΔZWU ≅ ΔVUW? Quadrilateral ZWVU is a square. Line segment ZW is parallel to line segment UV ∡ZUV and ∡WVU measure 90°. Line segment ZU ≅ Line segment WV

OpenStudy (anonymous):

OpenStudy (anonymous):

soo?

jimthompson5910 (jim_thompson5910):

one sec

OpenStudy (anonymous):

ok no prob

jimthompson5910 (jim_thompson5910):

If you were to divide a square by it's diagonal, what would you get

OpenStudy (anonymous):

two triangles

OpenStudy (anonymous):

right

jimthompson5910 (jim_thompson5910):

what kind of triangles

OpenStudy (anonymous):

so now what?

jimthompson5910 (jim_thompson5910):

what kind of triangles form

OpenStudy (anonymous):

right ones

jimthompson5910 (jim_thompson5910):

are they congruent triangles

OpenStudy (anonymous):

oh ya

jimthompson5910 (jim_thompson5910):

how do you know

OpenStudy (anonymous):

So now that we've established that, what now?

jimthompson5910 (jim_thompson5910):

well those two triangles are congruent (you can use the SSS property to show it's true) so that guarantees you'll have 2 congruent triangles

OpenStudy (anonymous):

What answer choice should I choose because that's not a choice

jimthompson5910 (jim_thompson5910):

what shape did we start with

OpenStudy (anonymous):

square

jimthompson5910 (jim_thompson5910):

so dividing up a square along its diagonal guarantees you'll have 2 congruent triangles

OpenStudy (anonymous):

so A?

jimthompson5910 (jim_thompson5910):

correct, that's one way to guarantee you'll get those 2 triangles to be congruent

OpenStudy (anonymous):

OK can I ask a few more there simple as you can see

jimthompson5910 (jim_thompson5910):

alright 2 more

OpenStudy (anonymous):

Which fact could you use to help prove that ΔAEDΔBEC using Side-Angle-Side? Line segment AD is parallel to line segment CB. Line segment CE over line segment DE is equal to line segment BE over line segment AE. The measure of line segment CE is equal to one-third times the measure of line segment DE. Line segment AD is congruent to line segment CB.

OpenStudy (anonymous):

Which fact could you use to help prove that ΔAEDΔBEC using Side-Angle-Side? Line segment AD is parallel to line segment CB. Line segment CE over line segment DE is equal to line segment BE over line segment AE. The measure of line segment CE is equal to one-third times the measure of line segment DE. Line segment AD is congruent to line segment CB.

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

whenever you use the SAS similarity postulate, you use the idea that the sides are proportional to each other

jimthompson5910 (jim_thompson5910):

so what does that mean

OpenStudy (anonymous):

They are similar

OpenStudy (anonymous):

so now what?

jimthompson5910 (jim_thompson5910):

if two triangles are similar, then the corresponding sides form a ratio

OpenStudy (anonymous):

so option B?

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

OK :) last one

OpenStudy (anonymous):

1.For the dilation, what was your scale factor? 2.For the reflection, across which line did you reflect it? 3.For the rotation, how many degrees was it rotated and in which direction?

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

I know the labels are wrong I already fixed the reflection and 180 degree counterclockwise turn

jimthompson5910 (jim_thompson5910):

what's your question about this one

OpenStudy (anonymous):

1.For the dilation, what was your scale factor? 2.For the reflection, across which line did you reflect it? 3.For the rotation, how many degrees was it rotated and in which direction?

jimthompson5910 (jim_thompson5910):

you have the dilation labeled on your paper

jimthompson5910 (jim_thompson5910):

the scale factor of the dilation

jimthompson5910 (jim_thompson5910):

the rotation you have is incorrect

OpenStudy (anonymous):

I know I told u I fixed that

OpenStudy (anonymous):

how do I find the scale factor for the dilation

jimthompson5910 (jim_thompson5910):

you already found it, it's 2

OpenStudy (anonymous):

Ok next question lol

OpenStudy (anonymous):

O must be losing my eyes lol

jimthompson5910 (jim_thompson5910):

if you were to rotate the original figure 180 degrees, it won't go from Q1 to Q4

OpenStudy (anonymous):

I fixed that already.How do I find out which line I reflected the image over.

jimthompson5910 (jim_thompson5910):

ok, the reflected image is in Q4 right?

OpenStudy (anonymous):

The image that I wrote was rotated is actually reflected, and the other new figure next to it was a 180 degree turn counterclockwise from the original

jimthompson5910 (jim_thompson5910):

i see

jimthompson5910 (jim_thompson5910):

so they're flipped

OpenStudy (anonymous):

Would that be correct?

jimthompson5910 (jim_thompson5910):

you're reflecting over the x-axis which is the line y = 0

jimthompson5910 (jim_thompson5910):

yes that's correct

OpenStudy (anonymous):

So what do I write. I reflected over line y=0?

jimthompson5910 (jim_thompson5910):

yep

OpenStudy (anonymous):

Thank You I wish u could help me more but a deal is a deal.

jimthompson5910 (jim_thompson5910):

hopefully you can use the info learned here to apply it to the others I don't want to do it all for you

OpenStudy (anonymous):

OK :) Thanks have a good night

jimthompson5910 (jim_thompson5910):

yw, you too

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