Question

Find slope of r^2=16Cos2(theta) with points (0,Pi/4) and (0,- pi/4). How to?

Answer 1

hey

Answer 2

To find the slope, take the derivative and plug in the given values

Answer 3

[HINT: you will be using \(chain ~rule\) here]

Answer 4

dy/dx = f'(theta)sin(theta) + f(theta)Cos(theta)
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f'(theta)cos(theta) - f(theta)Sin(theta)

Answer 5

Wait, what?

Answer 6

thats the equation of slope

Answer 7

Anyone?

Answer 8

so in other words I end up with (sin2(T)(sin(T) + 16Cos(T)(Cos(T))
----------------------------
Sin2(T)(Cos(T)) - 16Cos(T)(Sin(T)

Answer 9

but since its r^2, it could be all that (equation above) in a square root

Answer 10

@jim_thompson5910 Sorry if your busy...

Answer 11

Answer is 1... not sure how though