Abstract Algebra
H is a subset of R x R
H := {(x,y) s.t. y = 2x}
Prove H is a normal subgroup of R x R.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (zzr0ck3r):
I don't understand what the operation is
and if its multiplication if (x,y) is in H and (x',y') is in H
the y = 2x and y' = 2x' so yy' = 2*2xx' and thus not in H....
OpenStudy (kinggeorge):
Assuming R is the real numbers, the operation must be addition. Otherwise things go very badly with 0.
OpenStudy (zzr0ck3r):
right good call.
OpenStudy (zzr0ck3r):
so it would be the ordered pair (x+x',y+y')
and we would have y+y' = 2(x+x')?
OpenStudy (kinggeorge):
yes.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (zzr0ck3r):
and since R is commutative with addition H is a subgroup of an Abelian group and thus H is normal?
OpenStudy (zzr0ck3r):
every subgroup of an abelian group is normal.
OpenStudy (kinggeorge):
That would work.
OpenStudy (zzr0ck3r):
word. ty again kind sir:)
OpenStudy (kinggeorge):
You're welcome. Also, you still need to prove that it's a subgroup, but I assume you can handle that/already have.
Still Need Help?
Join the QuestionCove community and study together with friends!