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Mathematics 16 Online
OpenStudy (anonymous):

If T: (x, y) → (x - 7, y + 2), then T-1: (x,y) → _____. (no picture)

OpenStudy (zzr0ck3r):

just subtract 1 off each cooridinate

OpenStudy (zzr0ck3r):

its like f(x) = x - 7 so f(x) - 1 = x-8 and f(y) = y+2 so f(y)-1 = y+1 so you have T-1 = (x-8,y+1)

OpenStudy (zzr0ck3r):

(x-7,y+2) - 1

OpenStudy (zzr0ck3r):

understand?

OpenStudy (zzr0ck3r):

at least that what I think you asking :)

OpenStudy (zzr0ck3r):

T-1(x,y) is odd notation I think, for a function That is like (f -1)(x) I think we would say f(x)-1, but if these two things mean the same thing I think I know what its asking....

OpenStudy (anonymous):

sort of but i'm 99% sure that is in correct. though i do not have any idea how to do this, it is a multiple choice question and my options are: a. (-x over 7, y over 2) b. (-7x, 2y) c. (x- 7,y- 2) d. (x+ 7,y- 2) **by "over"i mean a fraction bar**

OpenStudy (zzr0ck3r):

is this inverse?

OpenStudy (loser66):

do you mean inverse of T?

OpenStudy (zzr0ck3r):

its d

OpenStudy (anonymous):

it doesnt say

OpenStudy (zzr0ck3r):

is it T raised to the -1?

OpenStudy (zzr0ck3r):

not T minus 1

OpenStudy (loser66):

which class are you in?

OpenStudy (zzr0ck3r):

\[T^{-1}\]

OpenStudy (zzr0ck3r):

not T-1

OpenStudy (anonymous):

geometry~

OpenStudy (zzr0ck3r):

it wants the inverse so we have f(x) = x-7 so f^(-1)(x) = x+7 and g(x) = x+2 so g^(-1)(x) = x-2

OpenStudy (anonymous):

heres the question. they aren't too specific..

OpenStudy (zzr0ck3r):

right

OpenStudy (loser66):

I'm with xx0ck3r , it' s d

OpenStudy (zzr0ck3r):

that ^-1 is the notation for inverse

OpenStudy (loser66):

*zz

OpenStudy (zzr0ck3r):

so read my comment with f(x) and g(x)

OpenStudy (anonymous):

ok thanks

OpenStudy (zzr0ck3r):

np

OpenStudy (zzr0ck3r):

when you want to show something raised to a power, use ^ like 2^3 = \[2^{3}\]

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