If T: (x, y) → (x - 7, y + 2), then T-1: (x,y) → _____.
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OpenStudy (zzr0ck3r):
just subtract 1 off each cooridinate
OpenStudy (zzr0ck3r):
its like f(x) = x - 7 so f(x) - 1 = x-8
and f(y) = y+2 so f(y)-1 = y+1
so you have T-1 = (x-8,y+1)
OpenStudy (zzr0ck3r):
(x-7,y+2) - 1
OpenStudy (zzr0ck3r):
understand?
OpenStudy (zzr0ck3r):
at least that what I think you asking :)
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OpenStudy (zzr0ck3r):
T-1(x,y) is odd notation I think, for a function
That is like (f -1)(x) I think we would say f(x)-1, but if these two things mean the same thing I think I know what its asking....
OpenStudy (anonymous):
sort of but i'm 99% sure that is in correct. though i do not have any idea how to do this, it is a multiple choice question and my options are:
a. (-x over 7, y over 2)
b. (-7x, 2y)
c. (x- 7,y- 2)
d. (x+ 7,y- 2)
**by "over"i mean a fraction bar**
OpenStudy (zzr0ck3r):
is this inverse?
OpenStudy (loser66):
do you mean inverse of T?
OpenStudy (zzr0ck3r):
its d
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OpenStudy (anonymous):
it doesnt say
OpenStudy (zzr0ck3r):
is it T raised to the -1?
OpenStudy (zzr0ck3r):
not T minus 1
OpenStudy (loser66):
which class are you in?
OpenStudy (zzr0ck3r):
\[T^{-1}\]
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OpenStudy (zzr0ck3r):
not T-1
OpenStudy (anonymous):
geometry~
OpenStudy (zzr0ck3r):
it wants the inverse
so we have f(x) = x-7 so f^(-1)(x) = x+7 and g(x) = x+2 so g^(-1)(x) = x-2
OpenStudy (anonymous):
heres the question. they aren't too specific..
OpenStudy (zzr0ck3r):
right
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OpenStudy (loser66):
I'm with xx0ck3r , it' s d
OpenStudy (zzr0ck3r):
that ^-1 is the notation for inverse
OpenStudy (loser66):
*zz
OpenStudy (zzr0ck3r):
so read my comment with f(x) and g(x)
OpenStudy (anonymous):
ok thanks
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OpenStudy (zzr0ck3r):
np
OpenStudy (zzr0ck3r):
when you want to show something raised to a power, use ^
like 2^3 = \[2^{3}\]