OpenStudy (anonymous):

Help

4 years ago
OpenStudy (anonymous):
4 years ago

mathslover (mathslover):

Hint : Use pythagoras theorem here. \(\textbf{base}^2 + \textbf{perpendicular}^2 = \textbf{Hypotenuse}^2 \)

4 years ago
mathslover (mathslover):

Recognize the base, perpendicular and hypotenuse from the figure. Plug in the values, find the value.

4 years ago
OpenStudy (luigi0210):

you may also know it as a^2+b^2=c^2 :P

4 years ago
OpenStudy (luigi0210):

Do you understand @effy_ ?

4 years ago
OpenStudy (anonymous):

@Luigi0210 yeah i know that, but when i do the problem i end up with the wrong answer :/

4 years ago
mathslover (mathslover):

Let us know, what you tried effy

4 years ago
OpenStudy (luigi0210):

Well show us your work buddy

4 years ago
OpenStudy (anonymous):

I love this stufff. U'll miss this later @effy_

4 years ago
mathslover (mathslover):

Have you recognized the base , the perpendicular and the hypotenuse correctly?

4 years ago
OpenStudy (anonymous):

@Luigi0210 @mathslover @Haiqa I got 15.. i dont think thats correct

4 years ago
mathslover (mathslover):

Its right.

4 years ago
OpenStudy (anonymous):

Dont doubt yourself too much

4 years ago
mathslover (mathslover):

\(9^2 + 12^2 = c^2\) \(81 + 144 = c^2\) \(225 = c^2\) \(c = \sqrt{225} = 15\)

4 years ago
mathslover (mathslover):

You're right effy. Good work :)

4 years ago
OpenStudy (anonymous):

@Haiqa @mathslover seriously!? my mom said its wrong. thanks mom

4 years ago
OpenStudy (anonymous):

Everyone makes mistakes

4 years ago
OpenStudy (anonymous):

Its all good, u got it right in the end

4 years ago
mathslover (mathslover):

Mam was just confusing you buddy, Usually elders try to analyze some one other, by confusing them with opposite answers. Have confidence on your work.

4 years ago
OpenStudy (anonymous):

lol @mathslover

4 years ago
OpenStudy (anonymous):

So true

4 years ago
OpenStudy (luigi0210):

Nice job buddy :P

4 years ago
OpenStudy (anonymous):

ty! can you guys help me with another?? @Luigi0210 @Haiqa @mathslover

4 years ago
OpenStudy (anonymous):

@effy_ Sure

4 years ago
OpenStudy (anonymous):

As long as its algebra...

4 years ago
OpenStudy (anonymous):
4 years ago

OpenStudy (anonymous):

Similar, same formula

4 years ago
mathslover (mathslover):

Post that as another question effy and yes, same process

4 years ago
mathslover (mathslover):

Just a little bit of change in positions ;)

4 years ago
OpenStudy (anonymous):

\[a^2+b^2=c^\]

4 years ago
OpenStudy (anonymous):

sorry c^2

4 years ago
OpenStudy (anonymous):

@mathslover ha ha :p

4 years ago
mathslover (mathslover):

:)

4 years ago
OpenStudy (luigi0210):

Haiqa's got you

4 years ago
OpenStudy (anonymous):

@mathslover @Luigi0210 @Haiqa it wouldnt happen to be 100?

4 years ago
mathslover (mathslover):

It would not be 100.

4 years ago
OpenStudy (anonymous):

b² = c²-a²

4 years ago
OpenStudy (luigi0210):

It's a little too big

4 years ago
mathslover (mathslover):

Hint : Hypotenuse is 125 m, base is 100 m.

4 years ago
OpenStudy (anonymous):

hint hint c=hyp.

4 years ago
OpenStudy (anonymous):

@mathslover @Luigi0210 @Haiqa ahh, I messed of the formula sorry

4 years ago
OpenStudy (anonymous):

75???

4 years ago
OpenStudy (luigi0210):

\[a^2+b^2=c^2\] \[100^2+b^2=125^2\]\[b^2=125^2-100^2\] \[b=\pm \sqrt{5625}\]

4 years ago
OpenStudy (anonymous):

its okay

4 years ago
OpenStudy (anonymous):

why is it i got 50.. @Luigi0210 @Haiqa @mathslover

4 years ago
OpenStudy (anonymous):

b=(125^2)-(100^2) 15625-10000=5625

4 years ago
OpenStudy (anonymous):

√5625=75

4 years ago
OpenStudy (luigi0210):

maybe you squared or subtracted wrong?

4 years ago
OpenStudy (anonymous):

@Luigi0210 subtracted wrong, haha. @Haiqa 75??

4 years ago
OpenStudy (anonymous):

what?!

4 years ago
OpenStudy (anonymous):

oh i thought i did something

4 years ago
OpenStudy (anonymous):

lol @Luigi0210 u really dont want to give the answer straight up

4 years ago
OpenStudy (anonymous):

that a question?

4 years ago
OpenStudy (anonymous):

Ur crazy @Luigi0210

4 years ago
OpenStudy (luigi0210):

D:

4 years ago
OpenStudy (anonymous):

Lol. @Luigi0210 I gave the answer though. U think @effy_ is gonna do that.

4 years ago
OpenStudy (luigi0210):

This never happened

4 years ago
OpenStudy (anonymous):

lol

4 years ago
OpenStudy (anonymous):

@Luigi0210 so whats the correct answer?? @Haiqa

4 years ago
OpenStudy (luigi0210):

These lips are sealed.. literally :l

4 years ago
OpenStudy (anonymous):

@Luis_Rivera noooD:

4 years ago
OpenStudy (luigi0210):

Who's Luis? :/

4 years ago
OpenStudy (anonymous):

@Luigi0210 WHOOPS. sorry luis

4 years ago
OpenStudy (luigi0210):

haha :P

4 years ago
OpenStudy (anonymous):

@Luigi0210 please? im so confseddd i keep thinking its c or d

4 years ago
OpenStudy (luigi0210):

We showed the work :/

4 years ago