Question

Help

Answer 1

Hint : Use pythagoras theorem here.

\(\textbf{base}^2 + \textbf{perpendicular}^2 = \textbf{Hypotenuse}^2 \)

Answer 2

Recognize the base, perpendicular and hypotenuse from the figure. Plug in the values, find the value.

Answer 3

you may also know it as a^2+b^2=c^2 :P

Answer 4

Do you understand @effy_ ?

Answer 5

@Luigi0210 yeah i know that, but when i do the problem i end up with the wrong answer :/

Answer 6

Let us know, what you tried effy

Answer 7

Well show us your work buddy

Answer 8

I love this stufff. U'll miss this later @effy_

Answer 9

Have you recognized the base , the perpendicular and the hypotenuse correctly?

Answer 10

@Luigi0210 @mathslover @Haiqa I got 15.. i dont think thats correct

Answer 11

Its right.

Answer 12

Dont doubt yourself too much

Answer 13

\(9^2 + 12^2 = c^2\)
\(81 + 144 = c^2\)

\(225 = c^2\)

\(c = \sqrt{225} = 15\)

Answer 14

You're right effy. Good work :)

Answer 15

@Haiqa @mathslover seriously!? my mom said its wrong. thanks mom

Answer 16

Everyone makes mistakes

Answer 17

Its all good, u got it right in the end

Answer 18

Mam was just confusing you buddy, Usually elders try to analyze some one other, by confusing them with opposite answers. Have confidence on your work.

Answer 19

lol @mathslover

Answer 20

So true

Answer 21

Nice job buddy :P

Answer 22

ty! can you guys help me with another?? @Luigi0210 @Haiqa @mathslover

Answer 23

@effy_ Sure

Answer 24

As long as its algebra...

Answer 25

Similar, same formula

Answer 26

Post that as another question effy and yes, same process

Answer 27

Just a little bit of change in positions ;)

Answer 28

\[a^2+b^2=c^\]

Answer 29

sorry c^2

Answer 30

@mathslover ha ha :p

Answer 31

:)

Answer 32

Haiqa's got you

Answer 33

@mathslover @Luigi0210 @Haiqa it wouldnt happen to be 100?

Answer 34

It would not be 100.

Answer 35

b² = c²-a²

Answer 36

It's a little too big

Answer 37

Hint : Hypotenuse is 125 m, base is 100 m.

Answer 38

hint hint c=hyp.

Answer 39

@mathslover @Luigi0210 @Haiqa ahh, I messed of the formula sorry

Answer 40

75???

Answer 41

\[a^2+b^2=c^2\]
\[100^2+b^2=125^2\]\[b^2=125^2-100^2\]
\[b=\pm \sqrt{5625}\]

Answer 42

its okay

Answer 43

why is it i got 50.. @Luigi0210 @Haiqa @mathslover

Answer 44

b=(125^2)-(100^2)
15625-10000=5625

Answer 45

√5625=75

Answer 46

maybe you squared or subtracted wrong?

Answer 47

@Luigi0210 subtracted wrong, haha. @Haiqa 75??

Answer 48

what?!

Answer 49

oh i thought i did something

Answer 50

lol @Luigi0210 u really dont want to give the answer straight up

Answer 51

that a question?

Answer 52

Ur crazy @Luigi0210

Answer 53

D:

Answer 54

Lol. @Luigi0210 I gave the answer though. U think @effy_ is gonna do that.

Answer 55

This never happened

Answer 56

lol

Answer 57

@Luigi0210 so whats the correct answer?? @Haiqa

Answer 58

These lips are sealed.. literally :l

Answer 59

@Luis_Rivera noooD:

Answer 60

Who's Luis? :/

Answer 61

@Luigi0210 WHOOPS. sorry luis

Answer 62

haha :P

Answer 63

@Luigi0210 please? im so confseddd i keep thinking its c or d

Answer 64

We showed the work :/