In ΔABC, m
SinB=22 SinC=52 a=30 22/b = 52/30 crossed multiplied and got 660 for SinB for b i got 52b. is 52 b my answer?
-1 >= sin (theta) >= 1 so.... sin b = 22?
I would point out that your problem statement doesn't give you 'c' it only gives you 'a', so you would need to calculate the angle A and then use your law of sines to get 'b'
12.69 would be my answer after dividing 660/52
Yes. That's the ticket. Law of Sines. Do you know that one autumnpoteet?
Slowly getting it haha.
180 - (22+52) = A
\[\frac{a}{\sin{A}}=\frac{b}{\sin{B}}\]
it gives me A already. why would i need a when im looking for b?
\[\frac{ \sin A }{ a } = \frac{ \sin B }{ b } =\frac{ \sin C }{ c}\]
No, it gives you side 'a', you need angle 'A'
so I am completely wrong? i was thinking of my last question hahah sorry.
For the law I just typed the secret is 1) get a pair of angle and side with the same letter and 2) pick a "fraction" for the other side of the proportion which contains the unknown you want.
i give up
A = 106
Angle A is 106. Now you know Angle A, side a (one fraction) and you know angle B (half of the fraction) (sin B / b). You can set a proportion now. Remember your numbers are sines of the angle measures, not the measures themselves.
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