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OpenStudy (anonymous):
OpenStudy (anonymous):
in the first one take 9 on the other side so it becomes sqrt t=7 and squaring on both sides u get t=49
OpenStudy (anonymous):
in the second one square both sides
so it becomes 6g-23=12-g
7g=35 so
g=5
OpenStudy (anonymous):
in the last one on squaring it becomes d^2=36
so on taking square roots on both sides it becomes\[d={\pm}6\]
OpenStudy (anonymous):
@aditya96 is that the answer?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
@aditya96 tysmmm. can you help me with 2 more?
OpenStudy (anonymous):
yes post it
OpenStudy (anonymous):
@aditya96
OpenStudy (anonymous):
in the first one sqaure both sides so u get a quadratic equation x^2-2x-15=0 which can be written as (x-5)(x+3)=0
so x=5 or -3
now substitute this values in ur equation and the value for which lhs=rhs is ur answer
so here only -3 satisfies the equation
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OpenStudy (anonymous):
in the second one
\[16099.44=15000(1+r)^{2}\]
according to the equation given
\[1.0732=(1+r)^{2}\]
so \[\sqrt{1.032}=1+r\]
so r=0.036