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Mathematics 7 Online
OpenStudy (anonymous):

Help??

OpenStudy (anonymous):

OpenStudy (anonymous):

in the first one take 9 on the other side so it becomes sqrt t=7 and squaring on both sides u get t=49

OpenStudy (anonymous):

in the second one square both sides so it becomes 6g-23=12-g 7g=35 so g=5

OpenStudy (anonymous):

in the last one on squaring it becomes d^2=36 so on taking square roots on both sides it becomes\[d={\pm}6\]

OpenStudy (anonymous):

@aditya96 is that the answer?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@aditya96 tysmmm. can you help me with 2 more?

OpenStudy (anonymous):

yes post it

OpenStudy (anonymous):

@aditya96

OpenStudy (anonymous):

in the first one sqaure both sides so u get a quadratic equation x^2-2x-15=0 which can be written as (x-5)(x+3)=0 so x=5 or -3 now substitute this values in ur equation and the value for which lhs=rhs is ur answer so here only -3 satisfies the equation

OpenStudy (anonymous):

in the second one \[16099.44=15000(1+r)^{2}\] according to the equation given \[1.0732=(1+r)^{2}\] so \[\sqrt{1.032}=1+r\] so r=0.036

OpenStudy (anonymous):

or 3.6%

OpenStudy (anonymous):

@aditya96 tysm

OpenStudy (anonymous):

ur welcome

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