Acetic acid contains carbon,hydogen and oxygen. 4324g of sample acetic acid on complete combustion gave 6.21g of CO_2 and 2.54g of H_2O. The Molecular mass of acetic acid is 60. Find (i) Empirical formula of acetic acid (ii) Molecular formula of acetic acid
Can you draw a table for finding empirical formula?
Step 1 = % of elements Step 2 =Mole Ratio step 3 = Simplest Ratio Step 4 = Establishing emp. formula
Although i am good at this........but this question is crazy....cant just get it done
Example Question : 1.8g of an organic compound on combustion gave 3.21g CO2 AND 1.322g H2O. Calculate Empirical Formula. Step 1 % of elements : C= 12/44 * 3.21/1.8 * 100 = 48.63% H=2/18*1.322/1.8 * 100 = 8.16 % O = 100-(48.63+8.16)=43.21% Step 2 Mole Ratio : C= 48.63/12 = 4.05 H= 8.16/1 = 8.16 O= 23.21/16 = 2.7 Step 3 Simplest Ratio : C=4.05/2.7 = 1.5 H=8.16/2.7 = 3 O=2.7/2.7 In order to get nearest whole no. ratio,all are multiplied by 2 Hence C=3 , H=6 , O=2 Step 4 Establishing Empirical Formula: C_3H_6_O_2
^here is a example
but the question i've asked is similar to this but it is entirely different ...it is giving crazy simplest ratio
Hold on
okay
4324g of sample acetic...... is the number correct?????
yes it is
1,69 gr C 0.28 gr H 4324-1,69-0.28=4322.03 gr of oxyxen !!!!! something is wrong!!!
it is from a question paper....and it is correct
is CO2 and H2O in gr or in Kgr ????
it is the 1st question i've asked
i see it. i still thing the numbers are wrong. try to take CO2 and H2O in Krg to see if it make sense....
4.324 kg acetic acid will produce only 6.21 g of CO2 and 2.54 H2O . Not possible, I think.
okay....this is what i think since you know the compound is acetic acid, then you should know it has a molecular formula C2H4O2 and an empirical formula of CH2O.....
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