What are the minimum,first quartile,median,third quartile,and the maximum of the data set?55,62,61,54,68,72,59,61,70 pls help thnx...
median is the middle result, if u had 5 results in the data: 1, 79, 15, 78, 16 rearrange from highest to lowest: 1, 15, 16, 78, 79 median is the middle one, so 16 in this case even thought the mean is more like 38 ish
u following so far?
@Lisad9708
I'm trying I'm kinda lost I have no clue just keep coming ill try my best to understand
ok, so here's your data: 55,62,61,54,68,72,59,61,70 and here's your data, re-arranged from highest to lowest: 54 55 59 61 61 62 68 70 72 so which is the middle number in this?
61?
yep, so there's 61, then there's 4 numbers on either side The median is the middle value of the data set. The lower quartile (Q1) is the median of the lower half of the data set.
so, median equation: median term = half of (n+1) so our data set has 9 values median term = half of (9+1) = half of 10 = 5th term in the data set (when arranged from highest to lowest) you guessed it right before it was 61 1st quartile term = quarter of (n+1) so our data set has 9 values 1st quartile term = 1/4 of (9+1) = 1/4 of 10 = 2.5th term = average of 2nd and 3rd values
so what does that equal?
or at least: what are the 2nd and 3rd values...?
Do I have square root or divide or times it
Third value is 68?
no, none of the above yet here's your data, arranged from highest to lowest: 54 55 59 61 61 62 68 70 72 what are the 2nd and 3rd values?
55,59?
yep, perfect now whats the average of them? (mean average)
= (55+59)/2 \[mean = \frac{(55 + 59)}{ 2 }\]
When u said average do I add them 2gether?
yes, then divide by 2
Pls don't give up on me I'm kinda slow its been awhile n math is not my thing.
that's ok, u should still be able to add 2 numbers together though and then divide that answer by 2
" n math is not my thing. " dude i was the same, but then i stopped thinking of it as numbers and more as logic puzzles, and it seemed to get easier
57
so 55+59 = 114 114/2 = 57 so your first quartile is 57
spot on dude
now: 3rd quartile term = 3 quarters of (n+1) so our data set has 9 values 3rd quartile term = 3/4 of (9+1) = 3/4 of 10 = 7.5th term = average of 7th and 8th values
so from highest to lowest: 54 55 59 61 61 62 68 70 72 what are the 7th and 8th values?
68+70?
yep now divide that by 2
69
yep, that's your 3rd quartile
now, ur max and min are your highest and lowest numbers in the data set 54 55 59 61 61 62 68 70 72 shoot
72
that's ur max done, props
72-54
yeah, and that's pretty much it for that q, yeah?
So minimum is 18 first quartile is 57 third quartile is 69 maximum is 72 I didn't get the medians
median was 61, first quartile 57, 3rd quartile 69 max 72... where did 18 come from...?
Oh I thought there is a minimum
minimum = lowest number in data set = 54
ah, i getcha now, range = 18
also, don't forget to close off your questions afterwards. button beside the "bump" at the top
Thnx for ur help I have some more question if its ok with u thnx again
sure, this ones getting a bit long, close and start a new one...?
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