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how do do a binomial expansion when x is in both terms
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find the coefficient of x in the expansion (2x+3/x)^6
Do you know \[\Large ^nC_r(q)^r(p)^{n-r}\] Where \((p+q)^n\)
yes, but I dont understand when there is an x in both terms oh and I'm trying to find the coefficient of x^3
The expanded form of that is \[64 x^6+\frac{729}{x^6}+576 x^4+\frac{2916}{x^4}+2160 x^2+\frac{4860}{x^2}+4320\]
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There's no x^3 term
It doesn't matter just consider them as two different terms and follow the formula. Also the first term has x and the second has 1/x , so when you expand it some of the x's get cancelled out.
You still can't get anything from there
ok thanks :)
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