Question

plse help me to solve this

Answer 1

@amistre64

Answer 2

what does the top equal at pi/2? or what does it limit to?

Answer 3

@amistre64
what is not clear to you in question, plse tell

Answer 4

the question is clear enough, but we need to know what the limit of the top part of the function is as x approaches pi/2

Answer 5

once we know that, we can then determine a, and also determine b

Answer 6

i calculate but not getting the limit of first function

Answer 7

see if a Lhopital helps out

Answer 8

the limit of the derivatives ...

Answer 9

\[\frac{1-sin^3x}{3cos^2x}\]
\[\frac{-3sin^2x~cosx}{-6sinx~cosx}\]
\[\frac{1}{2}\frac{sin^2x~\cancel{cosx}}{sinx~\cancel{cosx}}\]
at pi/2, = 1/2, therefore a needs to be 1/2

find the limit of the bottom such that a suitable b gets it to 1/2

Answer 10

therefore, a= 1/2
so what is the value of b

Answer 11

@msingh you should wait until amistre64 comes online. It's hard to continue other's stuff.

Answer 12

okay

Answer 13

@dan815 can you help him?

Answer 14

amistre already gave him answser, it is 0/0 indeterminate form, so use l'hospital rule

Answer 15

ok

Answer 16

nice display pic lol :)

Answer 17

okay @Loser66
i m trying to solve it using lhopstial rule

Answer 18

do u want to know where this lhospital rule ccomes from

Answer 19

hahaha... too many beautiful young lady here, there should be an old one to make them more beautiful, right?

Answer 20

basically you know both the top and bottom is going to 0/0 so, taking the derivative will tell you, which one of them is going to go to 0 first,
or what is the ratio of change between the derivatives, so u take lhospital rule to see if it simplifies

Answer 21

^ just the intuition, look at proof to understand more