Question

ellopse foci (0,+-2)(+-1,0)

Answer 1

the ellipse must have a centre of (x,y) to get those foci

Answer 2

My possible answers are: A. x^2/4+y^2, B. x^2/5+y^2, C. x^2+y^2/5 or D. x^2+y^2/4

Answer 3

an ellipse only has 2 foci, youve posted 3 .... or at least thats the way this is being interpreted by others

Answer 4

lol, youve posted 4, its sunday and i just cant count on the weekends

Answer 5

Its the co-ordinates of the 2 foci

Answer 6

the +- implies (0,a) and (0,-a)

Answer 7

Well +2 and -2 interpret to equal the same thing. The equation c^2=a^2-B^2 is supposed to be the correct way to go but the vertices of the vertical would be (0,a),(0,-A) and
co-verties (b,0),(-b,0) which confuses me so much since being C to solve is all that seems to be offered... >.<

Answer 8

so, you have been given a set of vertices, not foci

Answer 9

the equation of abc on an ellipse is a^2 = b^2 + c^2

Answer 10

Exactly, I'm not trying to solve just to
correctly format it

Answer 11

The foci would be c^2=A^2-B^2

Answer 12

Sorry no you're right lm thinking of solving for the foci

Answer 13

if all you are trying to do is pick the correct equation that has these verts ....

(+-p,0) suggests that under x^2 needs to be (p)^2
(0,+-q) suggests that under y^2 needs to be (q)^2

and the foci, again, does not follow the pythag thrm set up

Answer 14

c^2 = a^2 - b^2 is correct, yes

Answer 15

So which one do you think it is? I am kind of thinking B

Answer 16

if you want to solve for the foci, just remember slope = y/x, which corresponds to b/a in the conventional setup of these things

Answer 17

use the information given:\[\frac {x^2}{M}+\frac {y^2}{N}=1\]
when x=0, and y=+-2
\[\frac {0^2}{M}+\frac {(\pm2)^2}{N}=1\]
what does N have to be?

when x=+-1, and y=0
\[\frac {(\pm1)^2}{M}+\frac {0^2}{N}=1\]
what does M have to be?

Answer 18

For the top one it would have to be 4 to even out to equal on and the bottom one 0, right?

Answer 19

equal 1*

Answer 20

4 and 1, yes :)

so

x^2 + y^2/4 = 1 is the equation that fits

Answer 21

Thank you!

Answer 22

good luck ;)