Question

How would I go about factoring something like x^3+x-2?

Answer 1

\[x^3+x-2\]

Answer 2

\[= (x+1)^2(x-2)\]

Answer 3

how do you get there?

Answer 4

+x^2 -x^2 then, factor

Answer 5

got it?

Answer 6

if i distribute that out i get x^3-3x-2

Answer 7

show me yours step

Answer 8

\[(x+1)^2= x^2+2x+1\]
\[(x^2+2x+1)(x-2)=x^3+2x^2+x-2x^2-4x-2\]
\[=x^3-3x-2\]

Answer 9

so, go backward you have mine. that what you need: factor!!

Answer 10

now, I rearrange it for you

Answer 11

from yours: \[ x^3 +x -2 = x^3 +x^2-x^2+x-2\]

Answer 12

\[(x^3 +x^2) - (x^2-x+2)= x^2(x+1)-(x-2)(x+1)\]

Answer 13

oh i see it

Answer 14

\[=(x+1)(x^2-(x-2))=(x+1)(x^2-x+2)\]

Answer 15

thank you

Answer 16

good yw