Question

You're driving down the highway late one night at 17 when a deer steps onto the road 45 in front of you. Your reaction time before stepping on the brakes is 0.50 , and the maximum deceleration of your car is 11. How much distance is between you and the deer when you come to a stop?
What is the maximum speed you could have and still not hit the deer?

Answer 1

do you have answer for it?

Answer 2

For the distance between you and the deer I got 23m. But for the second part I have none.

Answer 3

do you know how to do you first part

Answer 4

sorry i meant to type do you know how to do the first part*

Answer 5

yeah i t took me a while but i got it.

Answer 6

for the second one you use this equation d=vit-vi^2/2a

Answer 7

\[d=vit-\frac{ vi ^{2} }{ 2a}\]

Answer 8

rearrange into the form \[Vi ^{2}+2ad-2aVit\]
solve for vi using the quatratic equation

Answer 9

forgot one more thing you need to plug known values then solve for vi

Answer 10

thanks. also for distance, should i factor in the reaction time or leave it as it is

Answer 11

can you show me the equation

Answer 12

for the reaction time?

Answer 13

yea

Answer 14

for the reaction time
d = speed x time
d = 17 x 0.5= 8.5 m

so 45 - 8.5m =36.5
i think this is what i did

Answer 15

yea thats right

Answer 16

so i should use this distance?

Answer 17

that is the distance he traveled before the hits the brakes

Answer 18

find the distance he travels while braking and use that and subtract from 36.5

Answer 19

thanks :)