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Chemistry 7 Online
OpenStudy (anonymous):

#1: Of the metals Ni, Au, Hg, and Ag, which will give up its electrons to copper (Cu) in a redox reaction? **table attached inside!*** A. Ni B. Au C. Hg D. Ag ***my answer; A. Ni what do u think @jim_thompson5910 :)

OpenStudy (anonymous):

table for #1 :)

OpenStudy (anonymous):

#2: The illustration attached depicts an electrochemical cell. Which of the following kinds of work would not be appropriate for this type of cell? A. electroplating B. splitting water into hydrogen and oxygen C. powering a light bulb D. purifying a metal ore ***my answer: C not 100% sure tho.. what do u think? :D

OpenStudy (anonymous):

#3: Which of the following reactions would occur at the anode in a voltaic cell? A. K+ (aq) + e- --> K (s) B. Cd2+ (aq) + Zn (s) --> Zn2+ (aq) + Cd (s) C. Mg (s) --> Mg2+ + 2e- D. Cu2+ (aq) + 2e- --> Cu (s) ***My answer: C is that correct? :)

OpenStudy (anonymous):

#4: Which of the following is the site of reduction when the dry cell is operating? ***see drawing attached!*** A. cardboard separator B. solid zinc layer C. negative terminal D. graphite rod **my answer: D is that right? :D

OpenStudy (anonymous):

#5: In the electroplating apparatus, where does the reduction reaction occur? A. on the surface of the anode B. in the solution C. on the surface of the battery D. on the surface of the cathode ***my answer; D not too sure on this one... what do u think? :D

thomaster (thomaster):

#1 I think you're right since nickel is the only one above copper

OpenStudy (anonymous):

ooh!Yay :) what do you think of the other ones? :D

thomaster (thomaster):

#2 electroplating, electrolysis of water, and purifying metal ore can be done in an electrochemical cell but powering a light bulb?? that's a weird answer xD The battery would power the lightbulb so i think you're right about this one

OpenStudy (anonymous):

aweosme :)

OpenStudy (anonymous):

what do you think of 3,4 and 5? :D

thomaster (thomaster):

#3 The anode is the electrode where oxidation takes place. C is the only oxidation reaction \(\sf reductant ~\underrightarrow{~~oxidation~~~}~Product+e^-\)

OpenStudy (anonymous):

wait so it's right? :) C is the answer? what about 4 and 5? :D

thomaster (thomaster):

#4 Oxidation occurs at the zinc Reduction occurs at the graphite rod. So D is correct

OpenStudy (anonymous):

yay :)

thomaster (thomaster):

#5 On the surface of the anode is correct so A

OpenStudy (anonymous):

okay i see :) thank you!! :D

OpenStudy (anonymous):

okay i see :) thank you!! :D

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