Question

Evaluate the definite integral
4
∫ 1/(x^2-6x+10) dx
2

Answer 1

Complete the square for the quadratic in the denominator.

Answer 2

This is an ideal situation for using partial fractions. Have you used the partial fractions method for integrating before?

Answer 3

@genius12, the denominator doesn't factor nicely though

Answer 4

i dont think so

Answer 5

denominator does not factor over integers, i would complete the square i think

Answer 6

just noticed that lol. @SithsAndGiggles

Answer 7

@shyllat,
\[\begin{align*}x^2-6x+10&=x^2-6x+9+1\\
&=(x-3)^2+1
\end{align*}\]
\[\int_2^4\frac{1}{(x-3)^2+1}~dx\]
Familiar with trig substitution?

Answer 8

ohhh ok yah i got it from here thank you!!