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Use properties of logarithms and solve the equation. Check for extraneous solutions. log(base3)(x+2) + log(base3)(x-2)=2
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start with \[\log_3((x+2)(x-2))=2\] then rewrite in equivalent exponential form as \[(x+2)(x-2)=3^2\] and finally solve the quadratic
you get \[x^2-4=9\] \[x^2=13\] and so \[x=\sqrt{13}\]
Thank you!! So exponential form is the base of the first log, 3, to the power of what the initial equation equaled, 2?
yes, after you use the property that \(\log(A)+\log(B)=\log(AB)\) to write as a single log
for example \(\log_5(x+6)=4\iff x+6=5^4\)
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Awesome! Thanks for your help!!
yw
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