Question

Which equivalence factor set should you use to convert 2.68 x 1011 atoms of Ag to grams of Ag?
Select one:
a. (2.68 x 1011 atoms Ag/1 mol Ag)(1 mol Ag/107.88 g Ag)
b. (1 mol Ag/2.68 x 1011 atoms Ag)(107.88 g Ag/1 mol Ag)
c. (1 mol Ag/6.02 x 1023 atoms Ag)(107.88 g Ag/1 mol Ag)
d. (2.68 x 1011 atoms Ag/6.02 x 1023 atoms Ag)(107.88 g Ag)

Answer 1

so you have to convert to moles, then multiply by Ag's Molar mass.
which one looks like it represents that?

Answer 2

b. (1 mol Ag/2.68 x 1011 atoms Ag)(107.88 g Ag/1 mol Ag)

Answer 3

hmm close. 2.68x10^11 is not one mole

Answer 4

Ok, so I need to convert to moles by dividing the number of atoms by Avogadro's number.
And then multiply that by the atomic weight and that will give me the weight in grams.
I just don't know what the equation would look like. :P

Answer 5

Wait... is it d?
d. (2.68 x 1011 atoms Ag/6.02 x 1023 atoms Ag)(107.88 g Ag)

Answer 6

yep, it's d

Answer 7

good jerb!

Answer 8

jerb? haha kinda reminds me of ermagerd. haha.. :P

Answer 9

haha "jerb" is from a south park episode

Answer 10

hahaha as you can tell, I don't watch south park. Even though I am from Colorado. :P

Answer 11

haha at least you know where the show is set in. I guess since amendment 64, no one remembers anything ;) haha jk