Question

How do I divide x^8+x^4/x? I keep getting x^8+x^3 and I do not think that is right...is that right? ugh thanks in advance

Answer 1

look back at the previous question you posted,i solved it there.

Answer 2

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Answer 3

the +x^3 part is right....but

what do you multiply 'x' by to get x^8?

Answer 4

ugh, I have this all over the place..I have no idea.

Answer 5

\[\large \frac{x^8+x^4}{x}\]\[\large \frac{x^8}{x} + \frac{x^4}{x}\] just solve each one separately

Answer 6

so for the first part you'd have \[\large x^{(8-1)} + x^{(4-1)}\]

Answer 7

i mean first and second* and @johnweldon1993 can continue....sorry john :|

Answer 8

10x?

Answer 9

no, you already did it before....go ahead and finish it @Jhannybean :)

Answer 10

I'm lost

Answer 11

I don't think you can add exponents when you're adding variables... :;\ only when multiplying.

Answer 12

oh damn

Answer 13

what would you get when you simplified \[\large x^{(8-1)} + x^{(4-1)}\] though?

Answer 14

x^7 + x^3

Answer 15

that is not what I get but, I think that;s it

Answer 16

okay, it can go a little further

Answer 17

See how you have a common base variable "x" ?

Answer 18

even though the two adding have DIFFERENT powers,we can FACTOR out a GFC, which in this case is x^3 :)

Answer 19

you guys rock! thanks

Answer 20

so you would have \[\large x^3(x^4+1)\]

Answer 21

I have not had math like this in like 20 years - still a work in prgress

Answer 22

Ohh haha yeah it happens. always have to keep practicing!

Answer 23

apparently...thanks again :)

Answer 24

noo problem!