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Chemistry 20 Online
OpenStudy (anonymous):

Which equivalence factor set should you use to convert 126 g C to atoms C? Pick One: a. (1 mol C/126 g C)(6.02 x 1023 atoms C/1 mol C) b. (1 mol C/12.01 g C)(6.02 x 1023 atoms C/1 mol C) c. (12.01 g C/1 mol C)(1 mol C/6.02 x 1023 atoms C) d. (12.01 g C/1 mol C)(6.02 x 1023 atoms C/1 mol C)

OpenStudy (anonymous):

Hmm i actually just did this in class too so im trying to work it out as to not give you a wrong answer

OpenStudy (anonymous):

I think we need to convert to moles by dividing the number of grams by Avogadro's number. And then multiplying that by something. I think it might be c or d? hmm... any thoughts?

OpenStudy (anonymous):

I believe your answer would be A because the way it is set up, mols would cancel out and you would be left with the number of atoms

OpenStudy (anonymous):

Hang on

OpenStudy (anonymous):

hahaha this question has had me stumped for almost ten minutes. ugh.

OpenStudy (anonymous):

This is how it would have to be done to go from mass to atoms

OpenStudy (anonymous):

(grams) x (6.02 x 10^23) / (mass of the element in grams)

OpenStudy (anonymous):

but that doesnt look like any of those =/

OpenStudy (anonymous):

Oh I see! So what I had suggested earlier was wrong. It needs to be from grams to atoms.

OpenStudy (anonymous):

Well, I think I'll try to google the answer. hahaha.

OpenStudy (anonymous):

Alright but I'm pretty sure you were right about c or d

OpenStudy (anonymous):

Google failed me... :(

OpenStudy (anonymous):

If you have to guess, go with c. It makes sense that 12.01 is 1 mol, times 1 mol which is 6.02 x 10^23 atoms

OpenStudy (anonymous):

so everything cancels out and you're left with atoms

OpenStudy (anonymous):

Alright! C it is! In fact, now that you just said that it looks to me as if C is the right answer! You are a saint!

OpenStudy (anonymous):

Haha alright, hopefully you got it

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