Which equivalence factor set should you use to convert 126 g C to atoms C? Pick One: a. (1 mol C/126 g C)(6.02 x 1023 atoms C/1 mol C) b. (1 mol C/12.01 g C)(6.02 x 1023 atoms C/1 mol C) c. (12.01 g C/1 mol C)(1 mol C/6.02 x 1023 atoms C) d. (12.01 g C/1 mol C)(6.02 x 1023 atoms C/1 mol C)
Hmm i actually just did this in class too so im trying to work it out as to not give you a wrong answer
I think we need to convert to moles by dividing the number of grams by Avogadro's number. And then multiplying that by something. I think it might be c or d? hmm... any thoughts?
I believe your answer would be A because the way it is set up, mols would cancel out and you would be left with the number of atoms
Hang on
hahaha this question has had me stumped for almost ten minutes. ugh.
This is how it would have to be done to go from mass to atoms
(grams) x (6.02 x 10^23) / (mass of the element in grams)
but that doesnt look like any of those =/
Oh I see! So what I had suggested earlier was wrong. It needs to be from grams to atoms.
Well, I think I'll try to google the answer. hahaha.
Alright but I'm pretty sure you were right about c or d
Google failed me... :(
If you have to guess, go with c. It makes sense that 12.01 is 1 mol, times 1 mol which is 6.02 x 10^23 atoms
so everything cancels out and you're left with atoms
Alright! C it is! In fact, now that you just said that it looks to me as if C is the right answer! You are a saint!
Haha alright, hopefully you got it
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