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Mathematics 21 Online
OpenStudy (anonymous):

Reviewing and in need of a refreshment.

OpenStudy (anonymous):

\[2\log_{5}3+\log_{5}5=\log_{5} x\]

OpenStudy (anonymous):

@jim_thompson5910 jimmy

OpenStudy (anonymous):

http://www.purplemath.com/modules/logrules.htm

OpenStudy (anonymous):

do you still need help?

OpenStudy (anonymous):

no(:

OpenStudy (anonymous):

thanks though.

jimthompson5910 (jim_thompson5910):

Use the log rules to get \[\large 2\log_{5}(3)+\log_{5}(5)=\log_{5}(x)\] \[\large \log_{5}(3^2)+\log_{5}(5)=\log_{5}(x)\] \[\large \log_{5}(9)+\log_{5}(5)=\log_{5}(x)\] ... ... ... \[\large x = ??\] From the looks of things though, it sounds like you got it

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