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Mathematics 21 Online
OpenStudy (anonymous):

What is the radius for the circle given by the equation x^2+(y-3)^2=21?

OpenStudy (anonymous):

It is just the square root of 21 \[\sqrt{21}\]

OpenStudy (anonymous):

Oh really? Thank you

OpenStudy (anonymous):

Yeah it's that easy :)

OpenStudy (anonymous):

Yes but do you understand why it is root(21)? :)

OpenStudy (anonymous):

Yes do you want me to explain?

OpenStudy (anonymous):

Sure

OpenStudy (anonymous):

Because if you understand why would you ask the question in the first place

OpenStudy (anonymous):

In general the equation of a circle in the standard form is written as follows \[(x-a)^{2} +(y-b)^{2} = r ^{2}\]

OpenStudy (anonymous):

Where a and b is just the ordered pair of the centre of a circle say the coordinates of the centre of the circle and then r is our famous radius but in the formula it is squared so we just take the square root of it to get to the real r

OpenStudy (anonymous):

That is correct :)

OpenStudy (anonymous):

Okay, I'm trekking. Thanks!

OpenStudy (anonymous):

Oh yes

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