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What is the radius for the circle given by the equation x^2+(y-3)^2=21?
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It is just the square root of 21 \[\sqrt{21}\]
Oh really? Thank you
Yeah it's that easy :)
Yes but do you understand why it is root(21)? :)
Yes do you want me to explain?
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Sure
Because if you understand why would you ask the question in the first place
In general the equation of a circle in the standard form is written as follows \[(x-a)^{2} +(y-b)^{2} = r ^{2}\]
Where a and b is just the ordered pair of the centre of a circle say the coordinates of the centre of the circle and then r is our famous radius but in the formula it is squared so we just take the square root of it to get to the real r
That is correct :)
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Okay, I'm trekking. Thanks!
Oh yes
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