Given 4.8 moles of a gas in a 1.8 L container, if the temperature is found to be 31 degrees Celsius, what is the pressure of the gas? (The ideal gas constant is 0.0821 L · atm/mol · K and 1 atm = 760 torr.)

Question

anonymous · Answer

n=4.8[mol]
V=1.8[L]
T=31[°C]=304.15[K]
R=0.0821[L⋅atm/mol⋅K]

anonymous · Answer

PV=nRT
P=nRTV

anonymous · Answer

P= (4.8) (.0821) (304.15) / (1.8)

anonymous · Answer

except I think that n might be wrong

anonymous · Answer

actually I guess we can leave it because it doesnt specify the gas

anonymous · Answer

Select one:
a. 6.79 torr
b. 66.55 torr
c. 6.79 x 100 atm
d. 6.66 x 101 atm

this is what I calculated: 66.588573333333333333333333 and so on with the 3's

anonymous · Answer

So I think the answer is b?

anonymous · Answer

Yeah that's what i would say