Question

For a process, the enthalpy change of a system is 1.25 x 10^5 J and the entropy change is 300.0 J/K. Calculate the free energy change of the system at 290 K.

Answer 1

dG = dH - TdS

Answer 2

I'm lost ... :/

Answer 3

the d just means "delta" which means change

H = enthalpy, S = entropy, G= gibbs free energy, T = temp

plug and solve

Answer 4

Thank you

Answer 5

no problem

Answer 6

\[DeltaG = DeltaH - T DeltaS\]
Here, Delta G is Gibbs Free Energy, Delta S is Enthalpy, T is tempereature (in Kelvins), and Delta S is entropy.
I think the answer should be 0.38*10^5.