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OpenStudy (anonymous):
Please help! What is the sum of the series? 20 on top and n-1 on the bottom of ∑(5-n)
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OpenStudy (anonymous):
did you mean n=1?
OpenStudy (anonymous):
@infinitemoes
OpenStudy (anonymous):
no it's a n-1 on the bottom of the sigma.
OpenStudy (anonymous):
\[\sum_{n-1}^{20} (5-n)\]
OpenStudy (anonymous):
yes exactly like that
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OpenStudy (anonymous):
It should be n=1 I am certain.
If we did this "manually" we would have 4 + 3 + 2 + ...
Right?
OpenStudy (anonymous):
alright..
OpenStudy (anonymous):
This is an arithmetic sequence b/c we are adding -1 over and over. There is a formula to solve this, Arithmetic Series Formula.
Do you know it?
OpenStudy (anonymous):
I think I got the answer. -110
OpenStudy (anonymous):
Let's see. The formula says: 1/2 the number of items times (first term + last term)
1/2 (20) (4 + -15)
10 (-11)
Good job.
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OpenStudy (anonymous):
thank you! :)
OpenStudy (anonymous):
You are welcome. All done? Thanks for the medal.
OpenStudy (anonymous):
Well I do have a couple more questions, but I'm gonna post them separate to this post.
OpenStudy (anonymous):
Of course.
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