Question

find the sum of the infinite series:

E 3(-1/3)^i
i=1

any help is appreciated, thanks!

Answer 1

\[3 (\frac{ 1 }{ 3 })^{i}\] ?

Answer 2

3(1/3)^i..... i being the variable, could also be n if needs be

Answer 3

Since the number being raised to a power has an absolute value of less than one, we can get a sum from the infinite series.

S(infinity) = a1 / (1-r)

a1 is the first value of the series, r is the common ratio (repeated multiplier)

Answer 4

swell, thank you!

Answer 5

Do you see? I don't mean to confuse and I can simplify.

Answer 6

naww its all good I got it, I wasn't sure what formula to use, thanks!

Answer 7

ok