Group Theory Challenge Problem! Let \(S_n\) be the group of permutations on \(\{1,2,...,n\}\), and let two players play a game. Taking turns, the two players select elements one at a time from \(S_n\). Players may only select elements that have not already been selected. The game ends when the set of selected elements generate \(S_n\). The player who made the last move loses. Who wins the game? [HINT: Think of this problem in terms of the largest possible set of elements you can have so that you don't generate the whole group.] [HINT 2: What are the orders of the maximal subgroups?]
This was a problem of the month offered by my undergraduate department where I was able to come up with the correct solution.
I post an easier group theory problem and only @KingGeorge looks, @KingGeorge posts one and you all are like flies....
im playing:)
If \(\large n\) is even, the player to select first would win. If \(\large n\) is odd, the player to select first would lose. Do I have the right idea?? D: No it's probably more math'y than that...
Definitely more mathy than that. Although that was also one of my first ideas when given this question.
the player who made the 2nd last move
Well, duh. But is that player the first or the second to have originally chosen?
Ummm can they remove more than one element at a time?
its the player that goes 2nd who wins
Only one at a time @swissgirl Show me a proof @dan815
Well, I'm off to bed. I'll leave you with the very vague hint, that while @zepdrix's idea is not the correct solution, you do need to keep even/odd in mind.
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