Question

Simplify the expression.
√6(√33+7)

A. √39+7√6
B. √198+7
C. 3√22+7√6
D. √198+7√6

Answer 1

@experimentX please help

Answer 2

I got C

Answer 3

oh my goodness.bad mistake.

Answer 4

it's not sqrt{37} it's sqrt{33} -_-

Answer 5

so the answer is not c then

Answer 6

\[\large \sqrt{6}(\sqrt{33}+7)\]\[\large \sqrt{a}*\sqrt{b} \implies \sqrt{6}*\sqrt{33}=\sqrt{198}\]\[\large \sqrt{6}*7 \implies 7\sqrt{6}\]altogether \[\large \sqrt{6}(\sqrt{33}+7)= \sqrt{198}+7\sqrt{6}\]

Answer 7

o ok thanks so much

Answer 8

Sorry about that... i wrote \(\sqrt{37} \) instead of \(\sqrt{33}\)

Answer 9

so you saying it was D and that is not write

Answer 10

right sorry

Answer 11

it came up wrong

Answer 12

it came up wrong? how come?

Answer 13

OMG! Jaan baji made a mistake!! =D

Answer 14

\[\Huge \color{Red}{\bf \bigstar}\]

Answer 15

You are right @Tabbiejack .\[\large \sqrt{198} = \sqrt{18*11} = \sqrt{9*2*11} = \sqrt{3*3*2*11} = 3\sqrt{22}\] So this would be \[\large 3 \sqrt{22}+7\sqrt{6}\] goodjob.