Calculate the no. of moles of Cl_2 produced at equilibrium , when 1 mole of PCl_5 is heated at 250°C , in a vessel having capacity of 10dm^3 . Kc for the reaction = 0.041

Question

anonymous · Answer

i just need to know the initial and equilibrium concentration

anonymous · Answer

PCl_5 (reversible --->) PCl_3 +Cl_2

saifoo.khan · Answer

Write the Kc equation first.

anonymous · Answer

$$Kc=\frac{ [PCl_3][Cl_2] }{ [PCl_5] }$$

saifoo.khan · Answer

PCl_5 (reversible --->) PCl_3 +Cl_2
initial mol         1                             0          0
Reacted            x                            x           x

Final moles        1 - x                         x         x

Now use the n=cv formula.

anonymous · Answer

is'nt it going to be 1/10=0.1
then   0.1-x       x     x

saifoo.khan · Answer

Maybe. 
I don't remember it correctly. 
I think yes go with 0.1

anonymous · Answer

plz can u confirm it by asking someone.. is it 1 or 0.1

saifoo.khan · Answer

Go with 0.1

anonymous · Answer

ok thanks!!