Question

sqrt of x + 2 minus 7 = sqrt of x + 9

Answer 1

\[\large \sqrt{x+2}-7 = \sqrt{x+9}\]?

Answer 2

Yep

Answer 3

first, do no harm
2nd, square everything
what'd jew get?

Answer 4

Do I square the 7 too?

Answer 5

\[\large \sqrt{x+2}-7 = \sqrt{x+9}\] square everything on both sides to get rid of the square root \[\large (\sqrt{x+2}-7)^2=(\sqrt{x+9})^2\]\\[\large (\sqrt{x+2}-7)(\sqrt{x+2}-7)=x+9\]foil method \[\large (\sqrt{x+2})(\sqrt{x+2})-(\sqrt{x+2})(7)-(7)(\sqrt{x+2})-(7)(-7)=x+9\] Simplify \[\large x+2-7\sqrt{x+2}-7\sqrt{x+2}+49=x+9\]

Answer 6

@Jhannybean that seems kinda longhand
... why not:

Answer 7

haha that's how i am able to check D:

Answer 8

after im done :(

Answer 9

lol

Answer 10

\[(\sqrt{x+2})(\sqrt{x+2})-(\sqrt{x+2})(7)-(7)(\sqrt{x+2})-(7)(-7)=x+9\]\[x+2-14\sqrt{x+2}+49=x+9\]\[x-14\sqrt{x+2}+52=x+9\]\[-14\sqrt{x+2}=-43\] bleh.

Answer 11

Shall i just....delete my posts...<_<

Answer 12

no!!

Answer 13

I'm definitely copying as we speak, lmao

Answer 14

No solution

Answer 15

oh LOL

Answer 16

How is it no solution O_o

Answer 17

Ohmahgerd D;

Answer 18

@.Sam. just throws out an answer :P

Answer 19

Yes, so helpful. Not.

Answer 20

yeah, my math didn't work out... thought i'd done something wrong hey
sorry @Jhannybean ... Jack's bad

Answer 21

Hey @Jhannybean what would the final answer be for x or did you get it lol

Answer 22

lol what? xD i think @Jack1 has it :P

Answer 23

no it doesnt work
LHS = x + 51 - (14(sqrt(x+2))
RHS = x+9

Answer 24

continuing from \[\large -14\sqrt{x+2}=-43\]\[\large \sqrt{x+2}=\frac{43}{14}\] square both sides \[(\sqrt{x+2})^2=(\frac{43}{14})^2\]\[\large x+2=\frac{1849}{196} \implies x= \frac{1457}{196}\] that's not right, i believe.

Answer 25

I don't even know anymore.

Answer 26

but does that work again in the initial eqn?

Answer 27

sqrt of x + 2 minus 7 = sqrt of x + 9
-55/14 = 4.0538 ish
-3.929 does not equal 4.0538 ish

Answer 28

OMG SO CLOSE.STUPID NEGATIVE SIGN.

Answer 29

I don't think that's the answer, try substituting it in, see if LHS = RHS

Answer 30

... i just did that

Answer 31

why do u hate me @.Sam. ...?

Answer 32

xDDD

Answer 33

I didn't, I just have a different thinking :)

Answer 34

is it coz i'm black?

Answer 35

:)

Answer 36

Lol, I don't even know that

Answer 37

and what's wrong with black?

Answer 38

LOL REVELATION?

Answer 39

Lmao okay next problem is sqrt of 2x+1 + qrt of 2x+6 = 5

Answer 40

\[[(\sqrt{x+2}-\sqrt{x+9})]^2=7^2 \\ \\ (x+2)-2\sqrt{(x+2)(x+9)}+(x+9)=49 \\ \\ 2x+11-2\sqrt{(x+2)(x+9)}=49 \\ \\ 2(x-\sqrt{(x+2)(x+9)})+11=49 \\ \\ x-\sqrt{(x+2)(x+9)}=19 \\ \\ (x-19)^2=(x+2)(x+9) \\ \\ 20=58x \\ \\ x=\frac{10}{29}\]

Answer 41

See, \(LHS \neq RHS\)

Answer 42

Jaan needs a sleep. She has been making mistakes all day.

Answer 43

=_=

Answer 44

she just wrote like 3 pages of squiggly equation posts, she deserves shiny shiny medals

Answer 45

@randomguy111 prettys sure your post's been hijacked, may want to close and pop ur new q in a new post...?