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Mathematics 20 Online
OpenStudy (amtran_bus):

(-i)^13?

terenzreignz (terenzreignz):

i (the imaginary unit) behaves much like any variable, it just has the added condition that \[\Large \color{green}i^2 = -1\]

terenzreignz (terenzreignz):

So, you could readily say that \[\Large (-\color{green}i)^{13}=(-1)^{13}\cdot \color{green}i^{13}\] as the laws of exponents would dictate :)

OpenStudy (amtran_bus):

So it is -i?

OpenStudy (anonymous):

yeah

terenzreignz (terenzreignz):

Yeah, that works :D \[\Large (-1)^{13}=-1\] \[\Large \color{green}i^{13}=\color{green}{i}^{12}\cdot \color{green}i = \color{green}i\]

OpenStudy (amtran_bus):

IS there a trick to remembering these i's?

terenzreignz (terenzreignz):

Sure there is :) If you're raising i to some exponent, you might want to divide that exponent by 4, and get the remainder.... for instance, what if we have \[\Large \color{green}i^{241}\] If you divide 241 by 4, what remains?

OpenStudy (amtran_bus):

60.25

terenzreignz (terenzreignz):

No, I'm asking for the remainder... but you could use that...

terenzreignz (terenzreignz):

If you're going to do it like that, then use this guide... if the quotient ends with a .25 (like this one) then the answer is i If it ends with a .5 (or .50) then it's -1 If it ends with a .75, then it's -i And finally, if you get an integer (no decimal part) then it's just 1.

OpenStudy (amtran_bus):

You rock

terenzreignz (terenzreignz):

:) To avoid confusion, let me just stress that that guide was for i... your question involved a -i so just adjust accordingly (like how I separated the -1^13 first)

OpenStudy (amtran_bus):

@terenzreignz , can you also help here? \[A _{n+1}=2A _{n}+1 \] for n= 0, 1, 2,

terenzreignz (terenzreignz):

hmm... we need a base step... maybe A0 is already given?

OpenStudy (amtran_bus):

I need to find A4

OpenStudy (amtran_bus):

A0 is 1

terenzreignz (terenzreignz):

Okay, good :) It REALLY helps to translate the maths terms into English :D Let's see how to do this... \[\Large A_{n+1}=2A_n+1\]

terenzreignz (terenzreignz):

A_n simply means the nth term, right? So what this is telling you, is that every term is twice the previous term, plus 1. So... A0 = 1 What's A1?

OpenStudy (amtran_bus):

3?

terenzreignz (terenzreignz):

Very good :) So now you know that A1 is 3 So what's A2 ?

OpenStudy (amtran_bus):

10?

terenzreignz (terenzreignz):

no... remember... every term is twice the previous term... plus 1...

OpenStudy (amtran_bus):

Duh. Sorry. 7

terenzreignz (terenzreignz):

okay Much better :D

OpenStudy (amtran_bus):

The answer is 31. Thanks.

OpenStudy (amtran_bus):

So reading in english does help!

terenzreignz (terenzreignz):

31? what...

OpenStudy (amtran_bus):

I need to find A4. So A2 was 7 A3 is 15 A5 is 31

OpenStudy (amtran_bus):

*A4

terenzreignz (terenzreignz):

ahh okay :D Then that was correct :D See? You pretty much did it yourself... the key was just understanding the maths problem, and maybe translating it into plain English :P

OpenStudy (amtran_bus):

Thanks

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