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a number can be squared ,show that this number is of the form
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\[\large\color{green}{4k\text{ or } 4k+1}\]
hence or otherwise show that if an interger is both a sqaure and a cube it can be written as \[\large\color{blue}{7k\text{ or }7k+1 }\]
@ParthKohli
basic number theory -elementary!!!
Suppose that the number (say \(n\)) is even.\[n = 2x \Rightarrow n^2 = 4x^2 \Rightarrow n^2 = 4k \tag{if x^2 = k}\]Continue with \(n\) as even
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Let's see how I go about the second one... hmm
okay good start then what about the other form
hint same trick
\(n\) as odd*
\[n = 2k + 1 \Rightarrow n^2 = 4k^2 + 4k + 1 \Rightarrow n^2 = 2(2k^2 + 2k) + 1\]:-P
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Whoops\[n^2 = 4(k^2 + k) + 1\]
|dw:1370268289474:dw|
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