Question

Help me! I will become a fan and give you a medal! (:

Answer 1

with what

Answer 2

Hold on let me get the equation done

Answer 3

ok

Answer 4

f your medal, and i dont need any more fans.

Answer 5

that made heaps of sense.

Answer 6

im to trilllllllllll

Answer 7

really ^

Answer 8

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc -\cot } = 2 \csc\]

Answer 9

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc -\cot } = 2 \csc \]

?

Answer 10

r u serious.... oh thats better

Answer 11

shut up lashaun. you a fake mf

Answer 12

them fighting words...

Answer 13

u dont even know me

Answer 14

give him some Lashaun

Answer 15

If you aren't going to help please leave

Answer 16

Shaylynnwalls im really sorry

Answer 17

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc -\cot } = 2 \csc \]

left hand side is becoming 0.

sure the problem doesnt have any typos ?

Answer 18

Its ok, it isnt your fault. Some people do not understand

Answer 19

And yes i am sure.

Answer 20

then, its a false identity !

Answer 21

Wait there is a typo. The second equation the bottom is csc theta plus cot theta

Answer 22

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc + \cot } = 2 \csc \]


like this ?

Answer 23

yep.

Answer 24

I think you do have to change everything to cosine and sine

Answer 25

good idea, but guess that would complicate things

Answer 26

lets take the LCM of denominator and simplify a bit

Answer 27

Ok, that makes more sense

Answer 28

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc + \cot } = 2 \csc \]

Left Hand Side :

\[\frac{ \sec (\csc + \cot) - \sec ( \csc - \cot ) }{ (\csc - \cot )(\csc + \cot ) } \]

Answer 29

i will give u













C===8 for free

Answer 30

simplify a bit

Answer 31

Ok let me write this down and than I can simplify.

Answer 32

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc + \cot } = 2 \csc \]

Left Hand Side :

\[\frac{ \sec (\csc + \cot) - \sec ( \csc - \cot ) }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ \sec \csc + \sec \cot - \sec \csc + \sec \cot }{ (\csc - \cot )(\csc + \cot ) } \]

Answer 33

So it would be sec times everything on the top?

Answer 34

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc + \cot } = 2 \csc \]

Left Hand Side :

\[\frac{ \sec (\csc + \cot) - \sec ( \csc - \cot ) }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ \sec \csc + \sec \cot) - \sec \csc + \sec \cot ) }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ \cancel{\sec \csc} + \sec \cot) - \cancel{\sec \csc} + \sec \cot ) }{ (\csc - \cot )(\csc + \cot ) } \]

Answer 35

yes ! you can do that...

Answer 36

you do in your way on ur notes. factoring sec is a brilliant idea.. go ahead :)

Answer 37

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc + \cot } = 2 \csc \]

Left Hand Side :

\[\frac{ \sec (\csc + \cot) - \sec ( \csc - \cot ) }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ \sec \csc + \sec \cot - \sec \csc + \sec \cot }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ \cancel{\sec \csc} + \sec \cot - \cancel{\sec \csc} + \sec \cot }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ 2 \sec \cot }{ (\csc^2 - \cot^2) } \]

Answer 38

Ok so once you do that you can simplify those to cot and csc if I did that correctly

Answer 39

yes ! bottom equals 1 as \(\csc^2 - \cot^2 = 1\)

Answer 40

\[\frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc + \cot } = 2 \csc \]

Left Hand Side :

\[\frac{ \sec (\csc + \cot) - \sec ( \csc - \cot ) }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ \sec \csc + \sec \cot - \sec \csc + \sec \cot }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ \cancel{\sec \csc} + \sec \cot - \cancel{\sec \csc} + \sec \cot }{ (\csc - \cot )(\csc + \cot ) } \]

\[\frac{ 2 \sec \cot }{ (\csc^2 - \cot^2) } \]

\[2 \sec \cot\]

\[2 \frac{1}{\cos} \frac{\cos}{\sin} \]

Answer 41

Than you would simplify the bottom equation by taking out the cos?

Answer 42

exactly !

Answer 43

complete solution, go thru :-


\(\large \frac{ \sec }{ \csc -\cot } -\frac{ \sec }{ \csc + \cot } = 2 \csc \)

Left Hand Side :

\(\large \frac{ \sec (\csc + \cot) - \sec ( \csc - \cot ) }{ (\csc - \cot )(\csc + \cot ) } \)

\(\large \frac{ \sec \csc + \sec \cot - \sec \csc + \sec \cot }{ (\csc - \cot )(\csc + \cot ) } \)

\(\large \frac{ \cancel{\sec \csc} + \sec \cot - \cancel{\sec \csc} + \sec \cot }{ (\csc - \cot )(\csc + \cot ) } \)

\(\large \frac{ 2 \sec \cot }{ (\csc^2 - \cot^2) } \)

\(\large 2 \sec \cot\)

\(\large 2 \frac{1}{\cos} \frac{\cos}{\sin} \)

\(\large 2\csc\)

Answer 44

Ok thank you so much! That makes so much sense now! The final answer would be 2csc!

Answer 45

np :)