Question

Given: In ∆ABC, DE || AC

Prove: BD/BA = BE/ BC

The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally.

Complete the proof by entering the correct statements and reasons.

Answer 1

@ganeshie8

Answer 2

that page is missing many things. maybe take a snapshot of ur desktop and attach :)

Answer 3

Oops I attached the wrong file! Here ya go. @ganeshie8

Answer 4

look at 4th row, it proves one set of angles are congruent.

Answer 5

so, in 3rd row, if we prove another set of angles are congruent - then, in 5th row, we can use AA similarity to establish triangles are similar. ok

Answer 6

Okay!

Answer 7

so, 3rd row you can have :-

3. \(\angle BDE \cong \angle BAC\) 3. By Corresponding Angles Postulate

Answer 8

5th row i want you to figure out, give it a try, il help if u get stuck :)

Answer 9

Okay, one sec let me look it over

Answer 10

So reflexive property was the 4th row, which is a=a right?

Answer 11

yes ! good work so far, keep going :)

Answer 12

What does it mean when it says "The converse of the SSS" in row 6?

Answer 13

it means, triangles are congruent, so you can take proportion of correspondign sides.

Answer 14

but, we will be using 3, 4 rows oly for filling 5th row

Answer 15

3rd row, we established one Angle is congruent
4th row, we established one Angle is congruent

Answer 16

so you can put this in 5th row :-

5. \(\triangle BAC \sim \triangle BDE\) 5. By AA similarity

Answer 17

see if that makes sense

Answer 18

@ganeshie8 - Sorry i lost internet because of the storms here! Thank you! I sort of understand, I'm really bad at math

Answer 19

its okay :) good to hear u understood a bit :)