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Mathematics 7 Online
OpenStudy (anonymous):

Can instantaneous velocity ever be negative?

OpenStudy (anonymous):

No, I don't believe it can

OpenStudy (andriod09):

No, think about a car. If its moving, it would be positive velocity, if it stops, it becomes neutral, not negative. A car can't go -25 m/h, can it? A car can go 25 m/h though. Good luck in your studies! \[\color{red}{Andy}\color{blue}{|}\color{purple}{(A)Andriod09}\]

OpenStudy (reemii):

it can. given that instantaneous velocity is \(v(t)=x'(t)\). |dw:1370275595826:dw| negative velocity means "going back in the other direction". Concl: it CAN if you consider the velocity as "vector". It CANNOT if you consider the "numerical" velocity..

OpenStudy (anonymous):

Thank you so much @reemii I was worried about that as a factor.

OpenStudy (reemii):

yw. a vector in \(\mathbb R\), that's a bit weird, so that's why usually ppl only think in "numerical" terms, like for a car (example above).

OpenStudy (anonymous):

@reemii even if an object is moving in the opposite direction, its instantaneous velocity would be zero.... -0=0 please correct me if i am wrong.

OpenStudy (reemii):

ok, if it goes "to the right" and then "to the left", there is a moment \(t_0\) in which hte velcity will be 0, that's right. but afterwards, it wil be moving, so the velocity is not zero.

OpenStudy (anonymous):

since the question asked was about the velocity of an object INSTANTANEOUSLY at rest, then it is always zero no matter its direction....

OpenStudy (reemii):

it is true that "instantaneously" it does not move much, but with this reasoning, you can prove this: it has a zero velocity at any time \(t\) between 0 and 1, therefore the it doesn't move! (therefore no car can move)

OpenStudy (reemii):

the "instantaneous velocity" is Defined as \(x'(t) = \lim_{h\to0}\frac{x(t+h)-x(t)}{h}\).

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