A small software company has two customer service representatives. After a week of oberservation, the supervisor of the customer service department determines that there is a 61% probability that a customer service representative will be on the phone with a customer at any given time. What is the probability of both representatives being on the phone at the same time? Round to the nearest percent if necessary.

A. 15%
B. 82%
C. 25%
D. 37%

Question

A small software company has two customer service representatives. After a week of oberservation, the supervisor of the customer service department determines that there is a 61% probability that a customer service representative will be on the phone with a customer at any given time. What is the probability of both representatives being on the phone at the same time? Round to the nearest percent if necessary.

A. 15%
B. 82%
C. 25%
D. 37%

anonymous · Answer

You need to do [probability of one] * [probability of the other] or .61 * .61.

terenzreignz · Answer

Since they're independent events (the presence of one rep on the phone doesn't affect the other) 
You just multiply their probabilities.

anonymous · Answer

So 61 x the 2 reps?

terenzreignz · Answer

No.... 61% times 61%
or
0.61 x 0.61

anonymous · Answer

I got 0.3721.

terenzreignz · Answer

yup. Just round that off, and you're good to go :D

anonymous · Answer

Ahh, I see what to do now. So 37%

terenzreignz · Answer

That's it :D
Nicely done ~