Question

Calculus - Determine the average value of f(x) over the interval form from x=a and x=b where

f(x) = 1/x a= 1/7 and b= 7

Answer 1

\[\frac{ 1 }{(b-a)}\int\limits_{a}^{b} f(x) dx\]

Answer 2

I got -100/7

Answer 3

result is 4.0390

Answer 4

\[\frac{ 7 }{ 48 } \int\limits_{1/7}^{7} \frac{ 1 }{ .5(7)^2}- \frac{ 1 }{ .5(1/7)^2 }\]

Answer 5

function is 1/x so it means to be solved in boundaries a and b

Answer 6

solutions of integral is 3.891

Answer 7

the rest is simple math

Answer 8

can you do the rest?

Answer 9

I got ln(7) - ln (1/7) which is 3.891...

Answer 10

then you multiply that by \[\frac{ 1 }{ b-a }\]

Answer 11

7-1/7= 6.857... which 1/8.857 * 3.891 is .5675...

Answer 12

yep

Answer 13

1/6.857 not 1/8.857

Answer 14

so as an exact answer it would be \[7\log 7/ 24\]

Answer 15

yep typo.