Question

The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X. What is the measure of angle ACB?

32°

60°

28°

16°

Answer 1

@wmckinely @jdoe0001 can you help? :)

Answer 2

Help please?? I'll give a medal!

Answer 3

@jdoe0001 can you please help?

Answer 4

give us a few secs :|

Answer 5

ok :) no rush I just wasn't getting a response ;)

Answer 6

usually because we don't have one yet :)

Answer 7

Ok :)

Answer 8

http://www.mathwarehouse.com/geometry/circle/images/tangent-secant/picture-of-intersection2.gif

Answer 9

I'm guessing the inner degree of 56, refers to the inner arc, which is the part that was throwing me off, from the picture, it doesn't look like, but I guess it's, so your "outter" arc is 176 and the smaller "inner" arc will be 56

Answer 10

But that's not an option...

Answer 11

yeah, I think is the angle B :/

Answer 12

:/ hold on I'm looking for a formula

Answer 13

the one in the picture IS the formula :/, just a matter of getting the "inner" arc

Answer 14

When I did that I got 8 :/ I'll just guess lol Thank you for your help! :)

Answer 15

lol

Answer 16

@Princess701 anyhow, found it

Answer 17

Found what? lol

Answer 18

the inner arc :)

Answer 19

yay! lol what is it? Or how did you find it?

Answer 20

if the angle of B is 56 and it's TOUCHING the circle, then the angle of the Arc it makes is twice that much, so the inner Arc is 112 degrees

Answer 21

so, that's the "inner" arc, and you are already given the "outter" arc, which is in the picture of 176 degrees

Answer 22

So it's 32!

Answer 23

176-112/2=32 :)

Answer 24

yes

Answer 25

Omg thanks you so much! haha you're a life saver :)

Answer 26

yw