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Help! i give medals Find the height and surface area of the right cylinder with the height equal to the diameter (volume is 128pi cubed)
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|dw:1370296123494:dw|
Well you know the volume is \(\pi r^2h\) you can use the dimensions you are given to solve for 'r'. Your surface area is \(2\pi rh + 2\pi r^2\) plug and chug.
so is it \[128\pi=pir2r\]
\[128\pi^3=\pi(r^2)(2r)\]
\[128\pi^3= \pi(2)r^3\]
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\[\frac{ 128\pi^3 }{ \pi }=\frac{ 2\pi(r^2) }{ \pi} \]
128pi^2=2r^2 64pi^2=r^2
8pi = r
r=8
8pi
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good?
thank you for your help much appreciated
yw
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