Question

Assume that lines that appear to be tangent are tangent. Point O is the center of the circle. Find the value of x. (Not drawn to scale)

Answer 1

m<O =36

Answer 2

A. 316
B. 272
C. 68
D. 44

Answer 3

Please explain how to do this problem =)

Answer 4

use this :-
sum of angles in a quadrilateral = 360

Answer 5

I don't understand :I

Answer 6

google and tell me what a quadrilateral is

Answer 7

I'm not stupid .-. A quad has 4 sides

Answer 8

then, use its property

Answer 9

you knw m<O = 36

Answer 10

I'm a bit confused, why are we talking quads when its a circle? Can't we just say a circle is 360?

Answer 11

dont u see a quadrilateral there ?

Answer 12

Well yeah but my teacher never mentioned quads, just arcs and stuff. Sorry =/

Answer 13

its okay, you need to use quadrilateral properties here

Answer 14

I'm used to the arcs and angles being inside the circles. But please continue =)

Answer 15

when you're doing circles, it is assumed that you knw very well about quadrilateral. nobody learns circles without first learning quadrilaterals

Answer 16

I do, I just wasn't introduced with using them both together.

Answer 17

okay good, wat made u think im treating u like that ha

Answer 18

Nevermind. How do I find the x? Would I subtract something from 360?

Answer 19

tell me this :-
for a circle, whats the angle formed between a tangent and radius ?

Answer 20

Umm, I'm not quite sure what your talking about. The arc? Central angle?

Answer 21

inscribed angle?

Answer 22

that angle is the angle between radius and tangent. it wud be 90 !

Answer 23

Oh! Is it a chord?

Answer 24

chord is different, chord cuts the circle at two points, and lies inside circle.

Answer 25

oh my goodness there is a geometry formula for this

Answer 26

you knw the 3 angles in the quadrilateral, you can find the fourth ?

Answer 27

144?

Answer 28

Yes !

Answer 29

you can use the formula above given by dumbcow also :)

Answer 30

That was easier than I though 0.o. But the formula looks confusing

Answer 31

but this method i like cuz we dont have remember formulas..

Answer 32

yea its easy once we do it once :)

Answer 33

Thanks ganeshie!

Answer 34

np :)

Answer 35

@ganeshie8 One more thing. This one confused me because they are using side measures? not angles?

Answer 36

yeah, its just pythagora.. let me draw and show u :)

Answer 37

Okay! Thanks!

Answer 38

\(OA^2 + AB^2 = OB^2\)

Answer 39

\(4000^2 + 17000^2 = OB^2\)

Answer 40

find OB first

Answer 41

then subtract the radius 4000 from OB, you would get distance from earth's surface BC

Answer 42

Okay, I'll give it a try

Answer 43

okie

Answer 44

The squares are confusing me. would I square them then add?

Answer 45

yes

Answer 46

guess i wud factor out 1000^2 frm both

Answer 47

\(4000^2 + 17000^2 = OB^2 \)

\(1000^2(4^2 + 17^2) = OB^2 \)

\(1000^2(16 + 289) = OB^2 \)

Answer 48

Wow, now I'm really confused. You do math a lot different then I do

Answer 49

\(1000^2(305) = OB^2 \)

\(1000 \sqrt{(305)} = OB \)

\(17464 = OB\)

Answer 50

its okay !

Answer 51

you can simplify stuff anyway u wish

Answer 52

now that OB, you need to subtract the radius 4000 from above to get wat they asking in the problem.

Answer 53

13,464

Answer 54

Thanks again! Its really kind of you to take you time to teach someone =) THANK YOU!!!

Answer 55

np :) you're welcome :))