Solve S = 4v2 for v.
I'm assuming the equation is \[\large S = 4v^2\]
yes i was a little confused becasue this is all they gave
you want the equation in the form of v= _____
yes
First divide both sides by 4 to get \[\large S = 4v^2\] \[\large \frac{S}{4} = v^2\] \[\large v^2 = \frac{S}{4}\] what's your next step?
next step be square rooting it? im really lost in this whole lesson
good, that undoes the square exponent
keep in mind that if you have something like x^2 = 4 then x = 2 or x = -2 since both are solutions (when you replace x with either value)
so this means \[\large v^2 = \frac{S}{4}\] turns into \[\large v = \pm\sqrt{\frac{S}{4}}\] after you take the square root of both sides
you can optionally write \[\large v = \pm\sqrt{\frac{S}{4}}\] as \[\large v = \sqrt{\frac{S}{4}} \ \text{ or } \ v = -\sqrt{\frac{S}{4}} \] but they mean the same thing
the first way is more compact
so it can be either negative or positively written?
yep
ok wow thank u! so much!
because (2)^2 = 4 and (-2)^2 = 4 so this shows you that x^2 = 4 has two solutions x = -2 or x = 2, which is really x = plus/minus 2
np
Solve M = 2x + 3y for y I also have a question like this, think you could help? explaining it helps I do online classes and really do not have any well explaining
how do you undo the +2x
wudnt u have to cancel it out
how would you cancel out 2x on the right side
subtract 2x from the y side also. Im not really sure
good
\[\large M = 2x + 3y\] \[\large M - 2x = 3y\] \[\large 3y = M - 2x\] what's next?
would we add 2, to the 2x to cancel it out and get the y all by itself
3y means 3 times y we move that 3 over by undoing the "times 3" what will undo the "times 3"?
wud we do 3x2 to find out what we re multiplying? im not sure
i never no which numbers to fill in to get the rest of the problem
let's say we start with the number 5 then we multiply it by 3 to get 5*3 = 15 how do we undo this and go back to 5?
15-10 wud get us back to 5
true, but what operation undoes multiplication what is the opposite of multiplication?
division
so if we multiply by 3 to do the complete opposite, we divide by 3
15 divided by 3
good
this means we divide both sides by 3
so the complete step by step picture looks like this \[\large M = 2x + 3y\] \[\large M - 2x = 3y\] \[\large 3y = M - 2x\] \[\large y = \frac{M - 2x}{3}\]
so at first, we undid the addition of 2x...so we subtracted 2x from both sides then we undid the multiplication of 3...which means we divided both sides by 3
we subtracted 2x fromthe 2x and 3y then divided 33 and divided it from 2x?
yes we go from 2x+3y to just 3y when you subtract off 2x you must do the same to the other side, which explains how it goes from M to M - 2x
we now have \[\large 3y = M - 2x\] then you divide both sides by 3 so 3y divided by 3 = y since the 3s cancel and dividing the right side by 3 means you can leave it as \[\large y = \frac{M - 2x}{3}\] since not much simplification is done anyway
so divide 2x and the 3 thts how we get it
correct and you leave the right side as it is
so this wud be everything after simplifying Y=M-2 over 3
yep \[\large y = \frac{M - 2x}{3}\]
oh it should be -2x and not just -2
2x ok got it thank u
yw
:)
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