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Mathematics 10 Online
OpenStudy (anonymous):

simplify (e^x/2)^2

ganeshie8 (ganeshie8):

apply the exponent to both numerator and denominator

OpenStudy (anonymous):

use rules of exponents (e^(x/2))^2

OpenStudy (anonymous):

so it would be (e^5x/2)?

OpenStudy (luigi0210):

Not exactly..

OpenStudy (anonymous):

how then? doesnt the exponent rule tell me to add the powers?

OpenStudy (luigi0210):

\[a^x*b^x=ab^{x+x}\] \[(a^x)^x=a^{x*x}\]

OpenStudy (anonymous):

so then (e^x)?

OpenStudy (anonymous):

@luigi you got the first one a bit wrong, but you're right on the the second one, and that's the important one

OpenStudy (anonymous):

yes, it is e^x

OpenStudy (anonymous):

ok then thank you for your help :)

ganeshie8 (ganeshie8):

its not like this ? \(\large (\frac{e^x}{2})^2\)

OpenStudy (jhannybean):

\[\large (e^{x/2})^2 \implies (e^{x/2})*(e^{x/2})=e^{2x/2} = e^x\]

OpenStudy (jhannybean):

and @Luigi0210 it's \[\large a^x*a^x=a^{2x}=(a^x)^2\]

OpenStudy (luigi0210):

._.

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