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simplify (e^x/2)^2
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apply the exponent to both numerator and denominator
use rules of exponents (e^(x/2))^2
so it would be (e^5x/2)?
Not exactly..
how then? doesnt the exponent rule tell me to add the powers?
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\[a^x*b^x=ab^{x+x}\] \[(a^x)^x=a^{x*x}\]
so then (e^x)?
@luigi you got the first one a bit wrong, but you're right on the the second one, and that's the important one
yes, it is e^x
ok then thank you for your help :)
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its not like this ? \(\large (\frac{e^x}{2})^2\)
\[\large (e^{x/2})^2 \implies (e^{x/2})*(e^{x/2})=e^{2x/2} = e^x\]
and @Luigi0210 it's \[\large a^x*a^x=a^{2x}=(a^x)^2\]
._.
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