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Chemistry 7 Online
OpenStudy (anonymous):

Which of the following represents positron emission? Select one: a. 3015P ---> 3014Si + ___ b. 23892U ---> 23490Th + ___ c. 147N + 42He --->178O + ___ d. 23490Th ---> 23491Pa + ___

OpenStudy (anonymous):

@abb0t

OpenStudy (abb0t):

It might help if you knew what \(positron~emission\) meant. So I ask, do you know what that means? :)

OpenStudy (anonymous):

Positron emission is a byproduct of a type of radioactive decay known as beta plus decay. According to wiseGEEK.com :P

OpenStudy (abb0t):

HINT: you're releaseing a positron.

OpenStudy (abb0t):

Well, yes it's a \(\beta^+\)-decay, but do you know what that actually means? Lol.

OpenStudy (anonymous):

A positron is an anti-electron: it has the same mass, but has a +1 change instead of a -1 charge. The remaining nucleus has one less proton and one more neutron

OpenStudy (abb0t):

Yep, so what that means is that a proton inside a radionuclide nucleus is converted into a neutron. Does that make sense?

OpenStudy (anonymous):

Somewhat, I'm not quite sure how that applies to the question above. :)

OpenStudy (anonymous):

so you are decreasing the atomic number by one.

OpenStudy (abb0t):

You're losing a positron. Which means -1 Do you know the notation? What it means when you have for instance, \(_{12}^{23}Mg\)??

OpenStudy (abb0t):

Yes, correct!!

OpenStudy (anonymous):

is it a?? :P

OpenStudy (abb0t):

Correct.

OpenStudy (anonymous):

Yay! Thank you so much @abb0t! :)

OpenStudy (anonymous):

No worries! It's better for all of us in the long-run! :)

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