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I don't know how to do this. Solve the equation. Identify any extraneous solutions. x= square root x +30
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\[x=\sqrt{x+30}\] \[x^2=x+30\]\[x^2-x-30=0\] solve the quadratic
How do you solve a quadratic?
this one factors as \[(x-6)(x+5)=0\] so \(x=6\) or \(x=-5\) then check the original equation you will see that \(6\) works and \(-5\) does not
so what is the extraneous idk what that means
it means the one that doesn't work
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6 works because \[6=\sqrt{6+30}\] \[6=\sqrt{36}\]\[6=6\] is true
oh thanks
-5 does not work because \[-5\neq \sqrt{-5+30}\] \[-5\neq \sqrt{25}\] \[-5\neq 5\]
yw
oh see i didn't know that was how it works
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