Simplify. n^6 · n^5 ÷ n^4 · n^3 ÷ n^2 · n
whatever is multiplied, keep those terms in NUMERATOR, \(\large n^6n^5n^3n\) whatever is divided, keep those terms in DENOMINATOR, \(\large n^4n^2\) now simplify them separately.
so i take n^6n^5n^3 and times them together
yeah, use this: \(\large x^a.x^b=x^{a+b}\) so, what is \(\large n^6n^5n^3n=....?\)
i got n^90 but i dont think thats right
you don't multiply the exponents, you ADD the exponents... try again?
n^15
YES ! :)
now, denominator ?
is it 4+2 or 4*2
when you multiply the bases, the exponents always gets ADDED, so it'll be 4+2 :)
so n^6
yup, now you have n^15/n^6 right ? know whqat to do next ?
i almost wanna say add the exponents or is it subtract
when bases get multiply , you ADD the exponents, but when bases get DIVIDED, you \(\color{green}{SUBTRACT}\) the exponents, so subtract :) \(\large \dfrac{x^a}{x^b}=x^{a-b}\)
so the answer is n^9
you are \(\huge \checkmark\) :)
XD thank you for your help
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