Question

Solve by complete the square:

y=-3x^2-9x-0.75

Answer 1

step one is to divide by \(-3\)

Answer 2

by "solve' do you mean "solve for \(x\) if \(-3x^2-9x-0.75=0\) "?

Answer 3

yes

Answer 4

then divide by \(-3\) and start with
\[x^2+3x+.25=0\]

Answer 5

you need the leading coefficient two be 1 to complete the square

Answer 6

then subtract to get
\[x^2+3x=-\frac{1}{4}\] and go right to
\[\left(x+\frac{3}{2}\right)^2=-\frac{1}{4}+\frac{9}{4}\] and work from there